Answer:
A. lower quartile is 3 and upper quartile is 8
im pretty sure but idkk
Step-by-step explanation:
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
More information is needed.
Set the number of chickens as x and number of cows as <span>y
</span>so the farmer has total 28 animals
so x+y=28
you know that since the animals are healthy
chickens will have 2 legs and
cows will have 4 legs
the total number of legs are 64
so 2x+4y=64
since you want to find the number of cows
so from the first equation <span>x+y=28
</span>we will get another equation <span>x=28-y
</span>then plug into <span>2x+4y=64
2(28-y)+4y=64
56-2y+4y=64
56+2y=64
-56 -56
2y=8
y=4
</span>
Answer:
nnn
Step-by-step explanation: