The volume of the cube is given by:
V=a³
where a is the side length
thus, given that:
a=4 inches
then
V=4³=64 in³
Answer: 64 in³
Answer:
h = 7 1/2
Step-by-step explanation:
2/5 h = 3
Multiply each side by 5/2 to isolate h
5/2 * 2/5 h = 5/2 *3
h = 15/2
h = 7 1/2
Section A) The AROC for Part A is 4.
h(x) = 4 * 1. 4 is your answer.
Section B) The AROC for Part B is 1.
h(x) = 4 * 1. 4 is your answer.
Part A: (Above)
Part B: There is no greater average change, both X's AROC is 4.
A.R.O.C: (Average Rate of Change)
I think this is right. Not 100% though
First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
Answer:
a
Step-by-step explanation:
