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2 years ago

15% of 20 girls who Play on the team also play another sport. How many girls play another sport?

Mathematics

1 answer:

jarptica [38.1K]2 years ago

6 0

Answer:

Step-by-step explanation:

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130% of what is 82.1? (Please show work!)

beks73 [17]

The answer is: 63.1538461538461538 ; (round to: 63.154) .
_____________________________________________________
130/100 * n = 82.1 ; Solve for "n" ;
_________________________________________
(1.3) n = 82.1 ;

n = 82.1 / 1.3 ;

n = 82.1 / 1.3 = 63.1538461538461538 ; round to 63.154 .
_________________________________________________

3 0

3 years ago

It takes 107,165 gallons of water to fill up the community pool. Selena's bathtub can hold 104 gallons of water. How many 104-ga

steposvetlana [31]

The answer is D) 1,030 45/104
You just have to take the amount of gallons it takes to fill up the pool and divide that by 104

3 0

2 years ago

Read 2 more answers

NEED HELP HERE PLEASE

loris [4]

1. The answer is C. cos180=-1, sin180=0. 2*(cos180+i*sin180)=2*(-1+0)=-2. Check every other answer, none of which gets -2.

2. The answer is C. cos270=0, sin270=-1. (You can draw out these angles to see). 2*(cos270+i*sin270)=2*(0-i)=-2i, as desired. Other choices don't work.

3. Answer A. Modulus of z is \sqrt(6^2+(-6)^2)=6*\sqrt(2). The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion. Theta=arctan(-6/6), and arctan(-1)=-pi/4, so theta=-pi/4=-pi/4+2pi=7pi/4. So A is the correct answer.

4. The answer is A. As above, cos270=0, sin270=-1. 3(cos270+sin270*i)=3*(0-i)=-3i. This problem is similar to question 2.

5. z1 = 7(cos 40° + i sin 40°), and z2 = 6(cos 145° + i sin 145°). z1*z2=7*6*(cos 40° + i sin 40°)*(cos 145° + i sin 145°)=42*(cos40*cos145-sin40*sin145+i*sin40*cos145+i*sin145*cos40). Use formula for sum/difference formula of cosines, cos40*cos145-sin40*sin145=cos(40+145)=cos185. Again, sin40*cos145+sin145*cos40=sin(40+145)=sin185. The answer is 42(cos 185° + i sin 185°).

6 0

3 years ago

Pls help quick i need this

irina [24]

Answer:

See explanation

Step-by-step explanation:

Q1-5.

1. Plane parallel to WXT is ZYU.

2. Segments parallel to $\overline {VU}$ are $\overline {ZY}, \overline {WX}$ and $\overline {ST}$

3. Segments parallel to $\overline {SW}$ are $\overline {VZ}, \overline {YU}$ and $\overline {XT}$

4. Segments skew to $\overline {}$ $\overline {XY}$ are $\overline {SV}$ and $\overline {VZ}$ (not lie in the same plane and not parallel)

5. Segments skew to $\overline {}$ $\overline {VZ}$ are $\overline {WX}$ and $\overline {XT}$ (not lie in the same plane and not parallel)

Q6.

a. $\angle 4$ and $\angle 10$ are the same-side interior angles, transversal k

b. $\angle 8$ and $\angle 11$ are alternate exterior angles, transversal m

c. $\angle 1$ and $\angle 4$ do not form any pair of angles

d. $\angle 2$ and $\angle 12$ are the same-side exterior angles, transversal k

e. $\angle 5$ and $\angle 7$ are corresponding angles, transversal j

f. $\angle 2$ and $\angle 13$ are alternate interior angles, transversal l

Q7.

$m\angle 1=m\angle 7=131^{\circ}$ (as vertical angle with angle 7)

$m\angle 2=180^{\circ}-131^{\circ}=49^{\circ}$ (as supplementary angle with angle 1)

$m\angle 8=49^{\circ}$ (as vertical angle with angle 2)

$m\angle 3=m\angle 1=131^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 4=m\angle 2=49^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 5=m\angle 7=131^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 6=m\angle 8=49^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 10=m\angle 16=88^{\circ}$ (as vertical angle with angle 16)

$m\angle 9=180^{\circ}-88^{\circ}=92^{\circ}$ (as supplementary angle with angle 16)

$m\angle 15=92^{\circ}$ (as vertical angle with angle 9)

$m\angle 14=m\angle 16=88^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

$m\angle 13=m\angle 15=92^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

$m\angle 12=m\angle 10=88^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

$m\angle 11=m\angle 9=92^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

Q8.

$m\angle 7=m\angle 9=105^{\circ}$ (as vertical angles)

$m\angle 8=180^{\circ}-105^{\circ}=75^{\circ}$ (as supplementary angle with angle 9)

$m\angle 10=m\angle 8=75^{\circ}$ (as vertical angles)

$m\angle 6=m\angle 8=75^{\circ}$ (as alternate interior angles when parallel lines a and b are cut by transversal c)

$m\angle 1=180^{\circ}-75^{\circ}-63^{\circ}=42^{\circ}$ (by angle addition postulate)

$m\angle 3=180^{\circ}-42^{\circ}-63^{\circ}=75^{\circ}$ (by angle addition postulate)

$m\angle 4=m\angle 1=42^{\circ}$ (as vertical angles)

$m\angle 5=m\angle 2=63^{\circ}$ (as vertical angles)

$m\angle 11=m\angle 4=42^{\circ}$ (as alternate interior angles when parallel lines a and b are cut by transversal d)

$m\angle 12=180^{\circ}-42^{\circ}=138^{\circ}$ (as supplementary angles)

$m\angle 13=m\angle 11=42^{\circ}$ (as vertical angles)

$m\angle 14=m\angle 12=138^{\circ}$ (as vertical angles)

3 0

2 years ago

If an amount of $100in a savings account increases by 10% percent again,is that the same as increasing by 20%?

damaskus [11]

Yes because 20% is the same as 10%*2

5 0

3 years ago

Read 2 more answers