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d1i1m1o1n [39]
3 years ago
13

Find the volume of a cube that has the following dimensions:length=2x^2 width=x^3 height=x^2-6x+5 A) 4x^7-3x^6+8x^5 B) 2x^12-12x

^7+10x^6 C) 2x^7+12x^6+10x^5 D) 2x^7-12x^6+10x^5
Mathematics
1 answer:
fomenos3 years ago
4 0

Answer:

Option D. 2x⁷ - 12x⁶ + 10x⁵

Step-by-step explanation:

From the question given:

Length (L) = 2x²

Width (w) = x³

Height (h) = x² - 6x + 5

Volume (V) =?

Volume (V) = length (L) x width (w) x height (h)

V = L x w x h

V = 2x² × x³ × x² - 6x + 5

V = (2x²) (x³) (x² - 6x + 5)

V = (2x⁵) (x² - 6x + 5)

Clear bracket

V = 2x⁷ - 12x⁶ + 10x⁵

Therefore, the volume of the cube is 2x⁷ - 12x⁶ + 10x⁵

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Answer:

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Step-by-step explanation:

Surface area of the rectangular box is expressed as S = 2(LW+LH+WH)

L is the length of the box = 90 cm

W is the width of the box = 50 cm

H is the height of the box= 90 cm

If there are error of at most 0.2 cm in each measurement, then the total surface area using differential estimate will be expressed as shown;

S = 2{(LdW+WdL) + (LdH+HdL) + (WdH+HdW)

Note that dL = dW = dH = 0.2 cm

Substituting the given values into the formula to estimate the maximum error in calculating the surface area of the box

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S = 2{18+10+18+18+10+18}

S = 2(92)

S = 184 cm²

Hence, the maximum error in calculating the surface area of the box is 184cm²

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