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zubka84 [21]
3 years ago
15

Plz help...................

Mathematics
1 answer:
tatiyna3 years ago
4 0
3/5 , 2/3, 5/7
60%, 66%, ~70%+
I gotcha
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Pls help I don’t get any of them
JulijaS [17]

Answer:

Step-by-step explanation:

28.   Area of the circle = πr^{2} where r is the radius of the circle.

       Given diameter = 14m, therefore radius = \frac{14}{2} = 7m

       Now area of the circle = 49\pi ^{2} or = 49 * 3.14 * 3.14 = 483.12m^{2}

29. Volume of cylinder = πr^{2}h = π*1.5^{2} * 3 = 6.75π cu. feet or 21.195 cu. feet

30. A ball resembles a sphere. Volume of the sphere = \frac{4}{3} \pi r^{3}

      Given diameter = 30inches; Therefore, radius = 15 inches

 Now, Volume of the ball = \frac{4}{3} \pi 15^{3} = 4500π cu. inches or 14310 cu.inches

7 0
3 years ago
The numbers 0.23350 has how many significant figures?
Alenkinab [10]

Significant figures are the digits that carry meaning to its measurement. Significant figures includes all the numbers excluding all the leading zeros, trailing zeros. All non zero digits are significant. Zeros between the non zero digits are significant. In a decimal number, trailing zeros are significant.

Now, consider the given number 0.23350

Since, in a decimal number all the trailing zeros are significant.

So, in the number 0.23350 there are five significant figures 2,3,4,5 and 0.

Therefore, there are 5 significant figures in the given number.

3 0
3 years ago
Read 2 more answers
6/9​ 9/12 wich one is bigger
Alexxandr [17]

Answer:

9/12

Step-by-step explanation:

because I is the biggest number

3 0
3 years ago
Read 2 more answers
Michael is 4 times as old as brandon and is also 27 years older than brandon<br> how old is brandon?
Komok [63]

Let the age of Brandon be x.

Therefore the age of Michael is 4x

Also the age of Michael is 27+x

So

4x=27+x

3x=27

X=9

Brandon age is 9years while Michael's age is 36

6 0
2 years ago
Find all real solutions and show work: <br> 2x^3-3x^2+18x-27=0
Amiraneli [1.4K]

Given:

The given equation is

2x^3-3x^2+18x-27=0

To find:

All the real solutions.

Solution:

We have,

2x^3-3x^2+18x-27=0

It can be written as

x^2(2x-3)+9(2x-3)=0

(2x-3)(x^2+9)=0

Using zero product property, we get

(2x-3)=0 and (x^2+9)=0

2x=3 and x^2=-9

x=\dfrac{3}{2} and x=\pm\sqrt{-9}

We know that x=\pm\sqrt{-9} is an imaginary number because there is a negative sign under the square root.

Therefore, x=\dfrac{3}{2} is the only real solution of the given equation.

5 0
3 years ago
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