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34kurt
3 years ago
13

I actually have 5 questions on the same thing, just different setups. But how would I go about solving them? .-.

Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0
<span>1)  2p = -2.
<span>     4p [ y - k ] = [ x - h) ]² --- > - 4 [ y + 5 ] = [ x + 5 ]²
2) </span></span><span>4p * (y - k) = (x - h)^2 </span>

<span>(h , k) is the vertex </span>

<span>The vertex is halfway between the focus and the directrix (when they're at their closest) </span>
<span>p is that distance </span>

<span>2 - 1 = 1 </span>
<span>4p = 1 </span>
<span>p = 1/4 </span>

<span>(1/4) * (y - k) = (x - h)^2 </span>
<span>y - k = 4 * (x - h)^2 </span>

<span>The vertex is at (6 , 3/2), since that's midway between (6 , 1) and (6 , 2) </span>

<span>y - 3/2 = 4 * (x - 6)^2 </span>
<span>y = (3/2) + 4 * (x - 6)^2 
</span><span>
4) </span><span>f(x) = (-1/16)*(x²)
</span><span>
5) </span><span>f(x) = −1/4 x2 − x + 5</span><span> 

</span>
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3 0
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Graph the function. For the function whose graph is shown below, which is the correct formula for the function? y = –x – 1 y = x
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You forgot to mention the graph.
So, I make the graph of both given functions and you will compare your graph with them.

First, y= -x-1  
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

4 0
3 years ago
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