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3 years ago

How much is 78ml when you turn it to litres

Mathematics

2 answers:

Xelga [282]3 years ago

8 0

Answer:

0.078 liters

Step-by-step explanation:

78ml=78/1000L

78ml=0.078ml

mylen [45]3 years ago

7 0

It is equal to 0.078 Litres

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Scateboard cost Rs450each in my local store,The shop keeper says if I buy 1 I can buyanother for only 7/9 of the normal price,ho

Whitepunk [10]

Answer:

the cost will be Rs 350

Step-by-step explanation:

The Scateboard cost Rs 450 each in the local store,The shop keeper says if I buy 1 I can buy another for only $\frac{7}{9}$ of the normal price. We are asked to determine the cost of a second scateboard .

Hence the cost will be $\frac{7}{9}$ of the normal cost that is

$\frac{7}{9} \times 450$

$7 \times 50$

$350$

the cost will be Rs 350

6 0

3 years ago

1. A line passes through the points (–4, –6) and (8, 4) a. Use point-slope form to write the equation of the line that is perpen

Ainat [17]

Answer:

I just know the formula for slope is y2-y1/x2-x1

Step-by-step explanation:

6 0

3 years ago

The sixth grade art students are making a mosaic using tiles in shapes of right triangles. Each tiles has the leg measures of 5.

Drupady [299]

Given:

Each right triangular tiles has the leg measures of 5.2 cm and 6 cm.

There are 150 tiles in the mosaic.

To find:

The area of the mosaic.

Solution:

We know that, the area of a triangle is:

$A=\dfrac{1}{2}\times Base\times height$

So, the area of Each right triangular tile is:

$A=\dfrac{1}{2}\times 5.2\times 6$

$A=\dfrac{1}{2}\times 31.2$

$A=15.6$

There are 150 tiles in the mosaic. So, the area of the mosaic is:

$Area=15.6\times 150$

$Area=2340$

Therefore, the total area of the mosaic is 2340 cm ².

5 0

3 years ago

Suppose that the terminal side of angle alphaα lies in Quadrant I and the terminal side of angle betaβ lies in Quadrant IV. If s

melamori03 [73]

Solution :

It is given that :

$\alpha$ lies in the first quadrant.

And $\beta$ lies in the fourth quadrant.

Since, $\sin \alpha = \frac{5}{13}$ and $\cos \beta = \frac{6}{\sqrt{85}}$ (given)

$\sin \alpha = \frac{5}{13}$

$\cos \alpha = \sqrt{1-\sin^2 \alpha}$

$\cos \alpha = \frac{12}{13}$

Similarly $\cos \beta = \frac{6}{\sqrt{85}}$

$\sin \beta = \sqrt{1-\cos^2 \beta}$

$\sin \beta = \sqrt{1-\frac{36}{85}}$

$-\frac{7}{\sqrt{85}}$ (IVth quadrant)

Therefore,

$\cos (\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta$

$=\frac{12}{13}\times \frac{6}{\sqrt{85}}-\frac{5}{13}\times \frac{-7}{\sqrt{85}}$

$= \frac{107}{13 \sqrt{85}}$

6 0

3 years ago

For sixth subtracted by two third

scZoUnD [109]

4/6 - 2/3 = 2/2 which reduces to 1 WHOLE

5 0

3 years ago

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How much is 78ml when you turn it to litres​

How much is 78ml when you turn it to litres