Answer:
The average distance between Earth and Pluto is same as average distance of Pluto from the Sun. This is 0.000628 light years, nearly.
Explanation:
The average distance obetween two planets is nearly the average distance of the outer planet from the Sun. Earth is inner to Pluto. Average Sun-Pluto distance = 5906.4 million km. Divide by 149597870 to get distance in Au. Further divide by 62900 to get distance in ly.
Answer:
-10
Step-by-step explanation:
-4 + -3 = -7
-7 + -2 = -9
-9 + -1 = -10
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Given :
Miki has 104 nickels and 88 dimes.
She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.
To Find :
Largest number of groups she can have .
Solution :
In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .
Now , factorizing both of them , we get :
Form above , we can say that common factors are :
Therefore , the largest number of groups she can have is 8 .
Hence , this is the required solution .
