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4 years ago

Evaluate to one decimal place

Mathematics

1 answer:

ANTONII [103]4 years ago

3 0

Answer:

<u>The correct answer is C. 1.6</u>

Step-by-step explanation:

Let's recall that e or Euler's number is a mathematical constant that is the base of the natural logarithm, in other words, the unique number whose natural logarithm is equal to one. The value of e is approximately 2.71828.

Now, replacing e, we have:

2.71828∧(1/2) = √2.71828 = 1.6 (Rounding to one decimal place)

<u>The correct answer is C. 1.6</u>

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andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR= $\sqrt{(-3-7)^2+(0-(-10))^2}$

QR= $\sqrt{(-10)^2+(10)^2}$

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QR=14.142136

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RS= $\sqrt{(12)^2+(-8)^2}$

RS= $\sqrt{144+64}$

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QS= $\sqrt{(-2)^2+(-2)^2}$

QS= $\sqrt{4+4}$

QS= $\sqrt{8}$ -------------------------------------(3)

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According to Pythagorean Theorem,

$RS^2 = QR^ +QS^2$

Substituting the values,

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208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

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$m\alpha I$

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