Ask question

Ask question

All categories

4 years ago

7

Evaluate to one decimal place

1 answer:

ANTONII [103]4 years ago

3 0

Answer:

<u>The correct answer is C. 1.6</u>

Step-by-step explanation:

Let's recall that e or Euler's number is a mathematical constant that is the base of the natural logarithm, in other words, the unique number whose natural logarithm is equal to one. The value of e is approximately 2.71828.

Now, replacing e, we have:

2.71828∧(1/2) = √2.71828 = 1.6 (Rounding to one decimal place)

<u>The correct answer is C. 1.6</u>

You might be interested in

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0

Tom [10]

Answer:

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

Step-by-step explanation:

The given equation is

$(2x+3)^2+8(2x+3)+11=0$

Let us treat this as a quadratic equation in $(2x+3)$ .

where $a=1,b=8,c=11$

The solution is given by the quadratic formula;

$(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute these values into the formula to obtain;

$(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}$

$(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}$

$(2x+3)=\frac{-8\pm \sqrt{20} }{2}$

$(2x+3)=\frac{-8\pm2\sqrt{5} }{2}$

$(2x+3)=-4\pm \sqrt{5}$

$(2x+3)=-4-\sqrt{5}$ or $(2x+3)=-4+ \sqrt{5}$

$2x=-3-4-\sqrt{5}$ or $2x=-3-4+ \sqrt{5}$

$2x=-7-\sqrt{5}$ or $2x=-7+ \sqrt{5}$

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

5 0

4 years ago

Can you please help me out on this

Aloiza [94]

Answer:

B)

Step-by-step explanation:

because 45= 1(45)

the rest don't show it on the table

3 0

3 years ago

Read 2 more answers

Select each correct answer.

egoroff_w [7]

A) reflect graph over x-axis (minus in front)
e) compress the graph to the x-axis (coefficient 1/2)
f) translate the graph to the right (x-9), minus between x and 9.

3 0

3 years ago

Laisha saved $20 053 She Spent $8995 how much does she have left

const2013 [10]

Answer:11,058

Step-by-step explanation:

Just subtract

8 0

3 years ago

What is the value of -3|15 - s| + 2s3 when's = -3

slamgirl [31]

<span>-3|15 - s| + 2s^3 when s = -3 is
</span>-3|15 - (-3)| + 2(-3)^3 = <span>-3|15 + 3| + 2(-27) = </span><span>-3|18| + (-54) = -3(18) - 54 = -54 - 54 = -108</span>

6 0

3 years ago