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3 years ago

23 20' 48" is the same as _____. Round to the nearest hundredth of a degree.

Mathematics

2 answers:

kow [346]3 years ago

7 0

Answer:

23.35

Step-by-step explanation:

pentagon [3]3 years ago

3 0

23° 20' 48" in degrees

Minutes are 1/60 of a degree and seconds 1/60 of a minute.

Let's convert the 48" to minutes.
48/60 = 0.8

23° 20' 48" ⇒ 23° 20.8'

Let's convert the 20.8' to degrees.
20.8/60 ≈ 0.3466667

23° 20.8' ⇒ 23.35°

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The drawing below shows a row of grocery carts that have been " nested" together. The carts are each 32in. Long. Each cart after

creativ13 [48]

Answer:

Length of Row of n cart = 11(n-1)+32 inches

The length of row for 20 nested carts will be = 11(20-1) +32 = 209 + 32 =241 inches.

Step-by-step explanation:

The length of one cart is 32 inches.

When you nest two cart, the length of the second cart will be 11 inches, so the total length of two nested cart will be 43 inches. From the this statements we can derive the following.

Length of Row of 1 cart = (1-1)*11+ 32 =32 inches

Length of Row of 2 cart =(2- 1)*11+32 = 43 inches

Length of Row of 3 cart = (3-1)*11 +32 = 54 inches

Length of Row of 4 cart = (4-1)*11 + 32 = 65 inches

Length of Row of 5 cart = (5-1)*11+32 = 76 inches

Length of Row of 6 cart = (6-1)*11+32 = 87 inches

Length of Row of 7 cart = (7-1)*11+32 = 98 inches

Length of Row of 8 cart = (8-1)*11+32 = 109 inches

Length of Row of 9 cart = (9-1)*11+32 = 120 inches

Length of Row of 10 cart = (10-1)*11+32 = 131 inches

Length of Row of n cart = (n-1)*11 + 32 =11(n-1)+32 inches

The relationship between the length of the row and the number of carts is given as Length of Row of n cart = 11(n-1)+32 inches

where n is the number of carts

The length of row for 20 nested carts will be = 11(20-1) +32 = 209 + 32 =241 inches.

4 0

3 years ago

Three years ago, Daniel bought a baseball card for $20. The baseball card gains a value of $10 each year for the next three year

torisob [31]

Answer:

The friend would pay $100

Step-by-step explanation:

The price of the card was $20 when Daniel bought it, it gained a value of $10 every year,

since Daniel bought it 3 years ago we will add $30 to $20 as the value increased by $10/year

so the price becomes $50, but his friend says he'll pay twice the value so,

$50×2= $100

8 0

3 years ago

Write a recursive rule for the sequence. 7, 6, 13, 19, 32, ...

allsm [11]

Answer:

recursive rule for the given sequence:

$a_n = a_{n-1}+a_{n-2}$ for n > 2

Step-by-step explanation:

Given the sequence:

7, 6, 13, 19, 32, ......

then;

First term $(a_{1})$ = 7

Second term $(a_{2})$ =6

third term $(a_{3})$ = 13 and so on..

You can see that:

$a_3 = a_1+a_2 = 6+7 = 13$

similarly for:

$a_4 = a_2+a_3 = 6+13 = 19$ and so on..

The recursive rule for this sequence is:

$a_n = a_{n-1}+a_{n-2}$ for n > 2

6 0

4 years ago

Test yourself 2

mafiozo [28]

Ok, so dy/dx=0 at the point (0,3) that is where x=0 and y=3.

$\int { 6x+6dx } \\ \\ =\frac { 6{ x }^{ 2 } }{ 2 } +6x+C\\ \\ =3{ x }^{ 2 }+6x+C$

$\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x+C$

Now, f'(x)=0 when x=0.

Therefore:

$0=C\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x$

Now:

$\int { 3{ x }^{ 2 } } +6xdx\\ \\ =\frac { 3{ x }^{ 3 } }{ 3 } +\frac { 6x^{ 2 } }{ 2 } +C$

$={ x }^{ 3 }+3{ x }^{ 2 }+C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+C$

But when x=0, y=3, therefore:

$3=C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+3$

7 0

3 years ago

Read 2 more answers

Please help........................

Rama09 [41]

Answer:

x = 7

Step-by-step explanation:

Since BD is the angle bisector of ∠ABC, then

∠ABD = ∠CBD, that is

2x + y = 14 + y ( subtract y from both sides )

2x = 14 ( divide both sides by 2 )

x = 7

8 0

3 years ago

Read 2 more answers