Please help me, I've been stuck on this problem forever and I need help! Please don't answer with something random to get points
. Answer the question please. I will mark Branliest.
Complete the two-column proof
Given: ∠1 is complementary to ∠2
→BD bisects ∠ADC
Prove: ∠1 is complementary to ∠3
Statement Reason
1. ∠1 is complementary to ∠2 1. ?
2. ? 2. Definition of complementary
3. ? 3. Given
4. ∠2 ≅ ∠3 4. ?
5. m∠2 = m∠3 5. ?
6. ? 6. Substitution property of equality
7. ? 7. ?
Complete the two-column proof
Given: ∠1 is complementary to ∠2
→BD bisects ∠ADC
Prove: ∠1 is complementary to ∠3
Statement Reason
1. ∠1 is complementary to ∠2 1. ?
2. ? 2. Definition of complementary
3. ? 3. Given
4. ∠2 ≅ ∠3 4. ?
5. m∠2 = m∠3 5. ?
6. ? 6. Substitution property of equality
7. ? 7. ?
1 answer:
You might be interested in
Answer:
The center is of the whole target.
Step-by-step explanation:
Given:
Diameter of the center = 5 inches
Diameter of the whole target = 25 inches
We need to find the part of the center to the whole target.
Solution,
Firstly we will find out the areas of center and whole target.
For center;
Diameter = 5 in
Radius of circle is equal to half of the diameter.
radius =
Now we know that the area of circle is equal to π times square of the radius.
framing in equation form, we get;
Area =
For whole target;
Diameter = 25 in
Radius of circle is equal to half of the diameter.
radius =
Now we know that the area of circle is equal to π times square of the radius.
framing in equation form, we get;
Area =
Now to find the part of the center to the whole target we will divide Area of center with Area of the target.
framing in equation form we get;
the part of the center to the whole target =
Hence the center is of the whole target.