All categories

2 years ago

What algebraic expression is used below. 5+3(2x-7)=5+6-21

Mathematics

1 answer:

Alla [95]2 years ago

7 0

It appears like the 3 was distributed through the parenthesis

You might be interested in

What is the percent 200% of 54

sweet-ann [11.9K]

So if 54 is 100% then 200% is double therefore 200% of 54 is 108

8 0

3 years ago

Read 2 more answers

Help me please! I would appreciate it! :)

GenaCL600 [577]

Answer:

y = 11 1/2

Step-by-step explanation:

7y - 63 = y + 3

-y. -7

6y - 63 = 3

+ 63. + 63

6y = 69

/6. /6

y = 11 1/2

3 0

2 years ago

Read 2 more answers

Complete the table of inputs for the given function.

Alecsey [184]

Answer:

a. $x = \frac{3}{8}$

b. $g(0) = 3$

c. $x = 1$

d. $g(3) = -21$

Step-by-step explanation:

Given

$g(x) = 3 - 8x$

Solving (a): When g(x) = 0

Substitute 0 for g(x)

$g(x) = 3 - 8x$

$0 = 3 - 8x$

Solve for 8x

$8x = 3$

Solve for x

$x = \frac{3}{8}$

Solving (b): when x = 0

Substitute 0 for x

$g(x) = 3 - 8x$

$g(0) = 3 - 8 * 0$

$g(0) = 3 - 0$

$g(0) = 3$

Solving (c): When g(x) = -5

Substitute -5 for g(x)

$g(x) = 3 - 8x$

$-5 = 3 - 8x$

Solve for 8x

$8x = 3 + 5$

$8x = 8$

Solve for x

$x = \frac{8}{8}$

$x = 1$

Solving (d): When x = 3

Substitute 3 for x

$g(x) = 3 - 8x$

$g(3) = 3 - 8 * 3$

$g(3) = 3 - 24$

$g(3) = -21$

3 0

2 years ago

the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the

Elanso [62]

1st number = x

2nd number = 3x

3rd number = 2x-10

x +3x + 2x-10 =92

6x - 10 = 92

6x =102

x = 102/6

x = 17

1st number = 17

2nd number = 17*3 = 51

3rd number = 17 *2 = 34-10 = 24

17 + 51 + 24 = 92

3 numbers are 17, 51 and 24

8 0

3 years ago

The Versatech Corporation has decided to produce three new products. Five branch plants now have excess production capacity. The

RSB [31]

Answer: provided in the explanation segment

Step-by-step explanation:

here i will give a step by step analysis of the question;

A: Optimization Formulation

given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5

Objective function: Minimize manufacturing cost (Z)

Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33

s.t

X11 + X12 + X13 + X14 + X15 = 600

X21 + X22 + X23 + X24 + X25 = 1000

X31 + X32 + X33 = 800

X11 + X21 + X31 <= 400

X12 + X22 + X32 <= 600

X13 + X23 + X33 <= 400

X14 + X24 <= 600

X15 + X25 <= 1000

Xij >= 0 for all i,j

Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.

cheers i hope this helps!!

3 0

3 years ago