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3 years ago

Need help it’s URGENT!

Mathematics

1 answer:

mamaluj [8]3 years ago

8 0

Answer:

either b or c

Step-by-step explanation:

i think

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What is the height of the building pictured below if its shadow is 100 ft. long?

Evgen [1.6K]

Yeah.. baby, do the SOH CAH TOA with the hula hoop

$\bf 
sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
$

so.. hmmm we have in the picture, an angle, and two sides,
actually, is the "adjacent" side, and the "opposite"

so.. which of those ratios give us only
the angle
the adjacent side
the opposite side?

ahhha!, is Ms tangent
so $\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(42^o)=\cfrac{h}{100}$

solve for "h"

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3 years ago

i ran 3hrs and 2 mins to run 26 miles if i ran at the same rate for the whole race how many minutes did it take to run each mile

oksian1 [2.3K]

7 minutes per mile.
8.57 miles per hour

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3 years ago

If f(x) = 2x² + 5, then what is the remainder when f (x) is divided by x – 10?

photoshop1234 [79]

Answer:

Step-by-step explanation:

x - 10 = 0

x = 10

f(10) = 2*10² + 5 = 2*100 + 5 = 200 + 5

= 205

Remainder = 205

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3 years ago

stephanie holds 30 cubes in a box. the cubes are 1/2 in each side. the box holds 2 layers with 15 cubes in each layer. what is t

TEA [102]

Answer:

3.75 Cubic Inches

Step-by-step explanation:

The volume of a single cube is 0.125 because the volume of a cube is its side length cubed, or to the third power. There are 30 cubes in the box, and 0.125 times 30 is 3.75

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3 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

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3 years ago

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