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tiny-mole [99]
4 years ago
5

Anybody know the answer

Mathematics
2 answers:
ycow [4]4 years ago
8 0
4/16=1/4
1/4=2/8

Answer: 1/4, even though it would be 2 slices at Pizza Palace it is still the same fraction or amout just divided diffrently.

Hope this helps:)
klemol [59]4 years ago
6 0
1/4 because it is basically the reduced fraction of 4/16 but is still equal to it
You might be interested in
I don’t know how to solve for p.
kumpel [21]

Answer:

p=12

Step-by-step explanation:

DBC = 180

ABE = 180

ABC + DBA = 180

ABC = (5p -28)

DBA + (12p -4)

CBD = ABC + DBA = 180

-------------------------------------------------

180 = (5p - 28) + (12p + 4)

180 = 17p - 24

204 = 17p

12 = p

p = 12

------------------------------------------------------

180 = (5(12) - 28) + (12(12) +4)

180 = 60 - 28 + 144 +4

180 = 180

4 0
3 years ago
No links GEOMETRY HELP PLEASE!! WILL MARK BRAINLEIST!<br> 10
Zinaida [17]

Given:

EFGH is a square.

To find:

The m\angle FHG.

Solution:

We know that all interior angles of a square are right angles.

m\angle EHG=90^\circ              (Right angle)

The diagonals of square are always the angle bisectors.

FH is a diagonal of the square. So, it bisects the angle EHG.

m\angle FHG=\dfrac{m\angle EHG}{2}

m\angle FHG=\dfrac{90^\circ}{2}

m\angle FHG=45^\circ

Therefore, the measure of angle FHG is 45 degrees.

4 0
3 years ago
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
3 years ago
Ignore the blue and 13. But I don’t understand dividing the polynomials. It says to complete the problem.
Virty [35]
OK the next step is to multiply 3r -1 by -7r
this gives us -21r^2 + 7r  and we write it below -21r^2 + 25r
and subtract 
This gives us  18r and we bring down the -6   to give
18r - 6

Finally we divide  18r by  -3r   to give  -6 then  add - 6 to the r^2 - 7r on the top 
then multiply -3r - 1 by -6 to give 18r - 6
subtraction then leaves nothing.

so the answer is r^2 - 7r - 6

4 0
3 years ago
Algebra II<br> line: 3(x - 2) &gt; 5x + 8
m_a_m_a [10]

Answer:

x < - 7

Step-by-step explanation:

Given

3(x - 2) > 5x + 8 ← distribute parenthesis on left side

3x - 6 > 5x + 8 ( subtract 3x from both sides )

- 6 > 2x + 8 ( subtract 8 from both sides )

- 14 > 2x ( divide both sides by 2 )

- 7 > x, hence

x < - 7

6 0
3 years ago
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