16.5 degrees below the starting temp, whatever that is. If its 0, then -16.5 degrees.
The first equation would be (.5)5-11=-8.5, because the metal has been cooling for 5 hours.
The device that 'aids' in the cooling would be -5-3=-8, because it is a separate variable that cools the metal, so the amount the device cools is independent of the natural cooling amount, and the equation is independent of the natural cooling equation.
You then add -8.5 and -8, because the device has lowered 8.5 degrees and 8 degrees. This equals -16.5 degrees, or a decrease of 16.5 degrees.
START WITH 1 COUNT BY ONES 1, 2, 3, 4, 5, 6
START WITH 8 COUNT BY ONES 8, 9, 10, 11, 12, 13
Answer:
0.3334 ft
Step-by-step explanation:
Measure the height and radius of the tank. The radius is the distance from the center of the tank to its outer edge. Another way to find the radius is to divide the diameter, or width, by two. Square the radius by multiplying the radius times itself and then multiply it by 3.1416, which is the constant pi.
- Given height and volume: r = √(V / (π * h)),
- Given height and lateral area: r = A_l / (2 * π * h),
- Given height and total area: r = (√(h² + 2 * A / π) - h) / 2,
- Given height and diagonal: r = √(h² + d²) / 2,
- Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2),
- Given volume and lateral area: r = 2 * V / A_l,
- Given base area: r = √(A_b / (2 * π)),
- Given lateral area and total area: r = √((A - A_l) / (2 * π)).
Hello!
The angles are supplementary meaning they add to 180°
a + 2a + 3 = 180
Combine like terms
3a + 3 = 180
Subtract 3 from both sides
3a = 177
Divide both sides by 3
a = 59
the answer is 59°
Hope this helps!
The answer should be 1y and -6y
