All categories

2 years ago

$185 DVD player 6% markup

Mathematics

2 answers:

sukhopar [10]2 years ago

5 0

After the markup it will be 196.1$

i think.....

if it is right dont forget to give me brainliest

dem82 [27]2 years ago

4 0

$196.10 dbdhdbrbhtbt

You might be interested in

Factorise the following quadratic equations

vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

In 13 - 17

Consider the factors of the constant term which sum to give the coefficient of the x- term

x² - x - 42 = (x - 7)(x + 6)

x² + x - 6 = (x + 3)(x - 2)

x² - 27x + 50 = (x - 25)(x - 2)

r² - 25 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , thus

r² - 25

= r² - 5² = (r - 5)(r + 5)

5 0

2 years ago

Read 2 more answers

Apply the markup for each item. Then, find the retail price. Round to two decimals places when necessary.

Alborosie

Answer:

$45 with 20% markup = $45 + $9 for a new total = $54

$7.60 with a 50% markup = $7.60 + $3.80 for new total = $11.40

Step-by-step explanation:

7 0

2 years ago

Simplify (a+b) ²-2ab

Scrat [10]

Answer:

a² + b²

Step-by-step explanation:

(a + b)² - 2ab ← expand parenthesis using FOIL

= a² + 2ab + b² - 2ab ← collect like terms

= a² + b²

6 0

2 years ago

I need help solving the last 2 questions please

Alborosie

A. 7.5 pages per hour B. $2.66 for one page

4 0

2 years ago

Read 2 more answers

A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste

Oxana [17]

Given that X be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02

Part A:

The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

 $P(X)={ ^nC_xp^x(1-p)^{n-x}} \\ \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\ \\ =1(1)(0.98)^{30}=0.5455$


Part B:

The mean of a binomial distribution is given by

 $\mu=np \\ \\ =30(0.02) \\ \\ =0.6$

The standard deviation is given by:

 $\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\ \\ =0.7668$


Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.

5 0

3 years ago