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GuDViN [60]
3 years ago
10

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Oxana [17]3 years ago
7 0
I hope its clear. Does this help??

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(a) We have three standard 6-sided dice, colored red, yellow, and green. In how many ways can we roll them to get a sum of 9? Th
Kisachek [45]
I believe that there are 23 different ways to get a total of 20. Then we need to find the number of ways to get each of the 23 different ways. For instance, one way is 6 6 1-1-1-1- 1-1-1-1: 101 / (21-8) = 45 (different ways to get this result) 10 different dice are rolled, giving the 101 in the numerator since the 6 is used twice, divide by 21, since the 1 is used 8 times, divide by 8! Etc., etc., etc. Final answers, add all these results together. I'm not sure about part B! I'm sorry!!!
6 0
3 years ago
What’s the answer please
Liono4ka [1.6K]

Answer:

to know what scale to use you divide the the highest score by the number of hozirontal line (feint/lighter drawn lines) which are 14.

so 260 ÷ 14 equals = 18.57

I then rounded the 18.57 to the nearest 10th = 20.

so the scale used is 20s

5 0
2 years ago
I need help solving this problem.
madam [21]

(f+g-k)(x) means to add the equations f(x) and g(x) then subtract k(x)

2x^2 + 3x + 4x - 9 = 2x^2 +7x -9

2x^2 + 7x - 9 - x^2 -7x = x^2 -9

The answer is : x^2 - 9

6 0
3 years ago
Read 2 more answers
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? A. {5, 8} B. {-5, -8} C. {3, 8} D. {4,
Sergeu [11.5K]

Answer:

Option D

The domain of the function is: {4, 7}

Step-by-step explanation:

We know that for polynomial functions like f(k) = k^2 + 2k + 1 its domain and its rank are all real numbers. However, for this case we are told that the function range is: the set {25, 64}

This means that the function is bounded.

Then the domain of f(k) are all possible values of k such that f(k) belongs to the interval {25, 64}.

To find the limit values of k then we do f(k) = 25

k^2 + 2k + 1 = 25

k^2 + 2k -24 = 0

Now we factor the expression:

(k + 6)(k-4) = 0

Then k = 4 and k = -6.

Now we do f(k) = 64

k ^ 2 + 2k +1 = 64\\\\k ^ 2 + 2k -63 = 0

We factor the expression:

(k + 9)(k-7) = 0

k = -9 and k = 7.

Finally we search between the options given an interval that matches.

The option that matches is option D {4, 7}

Finally, the domain of the function is: {4, 7}

5 0
3 years ago
Which polynomial is prime x3+11x2-3x-33 by grouping
gtnhenbr [62]
The answer to the question

4 0
3 years ago
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