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3 years ago

13

Michael has $1.95 totally in his collection, consisting of quarters and nickels. The number of nickels is three more than the nu

mber of quarters. How many nickels and how many quarters does Michael have?

2 answers:

madreJ [45]3 years ago

4 0

6 quarters = $1.50
9 Nickels = $0.45

Total= $1.95

Answer is 6 quarters and 9 nickels.<span />

Setler79 [48]3 years ago

3 0

He has 7 quarters and 9 nickels because $1.50+ $.45= $1.95.

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It looks easy i just dont know how to do it can someone help me out

Arada [10]

Answer:

16

Step-by-step explanation:

16+4x = 10 +14

-16 -16

4x = 8

/4 /4

x=2

8x=8(2)

=16

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2 years ago

Each of three coins has two sides, heads and tails. Represent the heads or tails status of each coin by a logical variable (A fo

jeka94

Answer:

(a) F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

Step-by-step explanation:

(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either

A is heads and the others are tails (AB'C')

B is heads and the others are tails (A'BC')

C is heads and the others are tails (A'B'C)

Hence, as a minterm expansion,

F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) To get the corresponding maxterm expansion, we convert to binary.

$F(A, B, C) = \sum (100, 010, 001) = \sum(4,2,1)$

The maxterm is the product of the complements.

$F(A, B, C) = \prod (0, 3, 5, 6, 7) = \prod(000, 011, 101, 110, 111)$

Expanding,

F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

3 0

3 years ago

F(x)=2x^2-3x+7 evaluate f(-2)

Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let p(x)=kpx+dp and q(x)=kqx+dq than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)

So you want:

−2kpk2q=0

and

kpkq=−1

and

2kpd2p−3kpdq+7=0

Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .

Answer: there are no such linear functions.

6 0

2 years ago

To solve a system of inequalities, you just need to graph each inequality and see wich points are in the overlap of the graphs.

GrogVix [38]

<h3>Answer: True</h3>

This is often how many math teachers and textbooks approach problems like this. The overlapped region is the region in which satisfies every inequality in the system. Be sure to note the boundary of each region whether you're dealing with a dashed line or a solid line. Dashed lines mean points on the boundary do not count as solution points, whereas solid boundaries allow those points as part of the solution set.

Side note: This is assuming you're dealing with 2 variable inequalities. If you only have one variable, you don't need to graph and instead could use algebra. Graphing doesn't hurt though.

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3 years ago

If my cat ate 1 to 3 cans of wet food what is the ratio in this statement?

Minchanka [31]

1 can of wet food
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3 cans of wet food
Or
1:3

8 0

3 years ago

Read 2 more answers