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valentina_108 [34]
3 years ago
6

A bank wishes to invest a $100, 000 trust fund in three sources: bonds paying 8%; certificates of deposit paying 7%; and first m

ortgages paying 10%. The bank wishes to realize an $8, 000, annual income from the investment. A condition of the trust is that the total amount invested in bonds and certificates of deposit must be triple the amount invested in mortgages. How much should the bank invest in each possible category?
Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

It is not possible to make the investment under the given conditions.

Step-by-step explanation:

Let x, y and z be the amounts invested in bonds, certificates of deposit and mortgages respectively.

<u>1st equation </u>

<em>“A bank wishes to invest a $100, 000 trust fund in three sources” </em>

x + y + z = 100,000

<u>2nd equation </u>

<em>“The bank wishes to realize an $8, 000, annual income from the investment and bonds paying 8%; certificates of deposit paying 7%; and first mortgages paying 10%” </em>

<em> </em>

0.8x + 0.7y + 0.1z = 8,000

3rd equation

<em>“the total amount invested in bonds and certificates of deposit must be triple the amount invested in mortgages” </em>

<em> </em>

x+y = 3z

and we have a <em>linear system of 3 equations with 3 unknowns </em>

    x +      y +      z = 100,000

0.8x + 0.7y + 0.1z = 8,000

    x +      y      -3z = 0

This system has a unique solution given by

x = -470,000  

y = 545,000

z = 25,000

Since x is negative, we deduct there is no way to do such an investment.

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The first term of an AP is -7 and the ratio of the eight term to the third term is 7:1 calculate the common difference
alukav5142 [94]

Answer:

the common difference is 6.

Step-by-step explanation:

Given;

first term of an AP, a = -7

let the common difference = d

The third term is written as;

T₃ = a + 2d

The eight term is written as;

T₈ = a + 7d

The ratio of the eight term to third term = 7:1

\frac{T_8}{T_3} = \frac{7}{1} = \frac{a+ 7d}{a + 2d} \\\\7 =  \frac{a+ 7d}{a + 2d}\\\\Recall, a = -7\\\\7 =   \frac{-7+ 7d}{-7 + 2d}\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = \frac{42}{7} \\\\d = 6

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3 years ago
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a baseball and a bat cost $1.10 and if this bat costs .10 cents more than the ball. how much did the ball cost?
kari74 [83]
<u>Define x:</u>
Let the cost of the ball be x.
Ball = x
Bat = x + 0.1

<u>The total cost is $1.10:</u>
x + x + 0.1 = 1.1
2x + 0.1 = 1.1
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<u>Find the cost of the bat and the ball:</u>
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Answer: The ball cost $0.50


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4 years ago
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