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madreJ [45]
3 years ago
11

The layer of gold coating on a ring should be 0.03 millimeters thick when the ring is completed. A coating of 0.021 millimeters

has already been applied. How many more millimeters of gold coating must be added to finish the ring?
A.) 0.018 millimeters
B.) 0.009 millimeters
C.) 0.18 millimeters
D.) 0.09 millimeters
Mathematics
2 answers:
STatiana [176]3 years ago
7 0

Answer:

0.0009 mm

Step-by-step explanation:

Arisa [49]3 years ago
6 0
The amount of gold coating in millimeters needed for the ring is the difference between the total coating and the coating that has already been applied. From the given above, that would be,
                                    0.03 mm - 0.021 mm = 0.009 mm
Thus, the answer to this question is letter B. 
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5 0
3 years ago
Four consecutive odd integers add up to -48. What is the least of these integers?
Semmy [17]

Answer:

-9

Step-by-step explanation:

Four consecutive odd integers be (2x - 3),(2x -1),(2x + 1),(2x + 3)

2x-3 + 2x - 1 +2x+1 + 2x+3 = -48

2x + 2x + 2x +2x - 3 - 1 + 3 + 1 = -48

8x = -48

x = -48/8

x = -6

Least of these integer = 2x + 3 = 2*(-6) + 3 = -12 + 3 = -9

3 0
3 years ago
Zoom in to see it better
iren [92.7K]
A ghhuhggfgghhhhhjkhhj
4 0
2 years ago
Read 2 more answers
Find the vector that has the same direction as 3, 2, −6 but has length 2.
Nata [24]

Answer:

The vector is \vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right).

Step-by-step explanation:

We can determine the equivalent vector (\vec r), dimensionless, by means of the following formula:

\vec r = \frac{\vec u}{\|\vec u\|} \cdot \|\vec r\| (1)

Where:

\vec u - Original vector, dimensionless.

\|\vec u\| - Norm of the original vector, dimensionless.

\|\vec r\| - Norm of the new vector, dimensionless.

The norm of the original vector is determined by the following definition:

\|\vec u\| = \sqrt{\vec u\,\bullet \,\vec u} (2)

If we know that \vec u = (3, 2, -6), then the norm of the original vector is:

\|\vec u\| = \sqrt{(3)\cdot (3)+(2)\cdot (2)+(-6)\cdot (-6)}

\|\vec u\| = 7

If we know that \|\vec r\| = 2, then the new vector is:

\vec r = \frac{2}{7}\cdot (3,2,-6)

\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)

The vector is \vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right).

7 0
3 years ago
Suppose you want to be sure that the total cost of the three items does not go over a certain amount. How can you use estimation
Bond [772]

Answer:

i don't konw

Step-by-step explanation:

5 0
3 years ago
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