Answer: A and B I think
Step-by-step explanation:
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Answer:
1
Step-by-step explanation:
x is 1 and y is 1 and the total is three so 1
<h3><em>i </em><em>hope</em><em> it</em><em> helps</em><em> u</em><em> ☠️</em></h3>
