Answer:
x=2, y=3
Step-by-step explanation:
This is a <u>system of equations</u>.
To solve a system of equations, we use the substitution method.
We can plug in the first equation, , into the value for <em>x</em> in the second equation. Now, the second equation looks like this:
We simplify and solve for <em>y</em>:
→
→
→
Now, we plug in the value for <em>y</em>, which is 3, into either equation. I will just use the first equation:
→
→
Let me know if my explanation is unclear.
Answer:
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).
