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fenix001 [56]
3 years ago
7

Which pair of angles listed below are adjacent angles?

Mathematics
2 answers:
murzikaleks [220]3 years ago
3 0
I'm just gonna say that its maybe 1 and 4. I'm not sayig its correct, its just that i think thats what it is.
sashaice [31]3 years ago
3 0
The correct answer is for this problem is 1 and 4 
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Please help and thank you
d1i1m1o1n [39]
# ov wekz..... \_ >_○ _/
5 0
2 years ago
1.5 &gt; 0.75x + 1 <br> what is x
motikmotik

Answer:

2/3 > x

Step-by-step explanation:

0.5 > 0.75x

2/3 > x

6 0
2 years ago
Point D is between Points E and F. DE = 3x + 9, DF = 12x - 1<br> and EF = 38. Find DE and DF.
jarptica [38.1K]

Answer:

DE = 15

DF = 23

Step-by-step explanation:

E___D___F

EF = DE + DF

38 = (3x +9) + (12x-1)

38 = 15x + 8

15x = 38 - 8

15x = 30

x = 30/15

x = 2

DE = 3x + 9 = 3(2) + 9 = 6 + 9 = 15

DF = 12x - 1 = 12(2) - 1 = 24 - 1 = 23

I hope I helped you^_^

7 0
3 years ago
Your English teacher has decided to randomly assign poems for the class to read. The syllabus includes four poems by Shakespeare
Tresset [83]
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.

So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.

At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39

The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
6 0
3 years ago
Help me please (20 points) (2 questions) PLEASE (picture below)
Wittaler [7]
The first question is 2, 12, and 14 but i’m sorry i don’t know the second :(
7 0
3 years ago
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