Question

They have a rectangle ABCD as shown below, where AB = 24cm BC = 10cm and AE = 13cm

Answer 1

Answer:

A. Area of ABCD = 240 $cm^{2}$

B. 60 cm

C. 36 cm

D. 50 cm

Step-by-step explanation:

Given: AB = 24cm BC = 10cm and AE = 13cm.

A.  Since a rectangle is a 2 dimensional figure, it has no volume but area.

So that,

the area of the rectangle ABCD = length x width

                                                     = 24 x 10

                                                     = 240 $cm^{2}$

B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.

$BD^{2}$ = $BC^{2}$ + $DC^{2}$

       = $10^{2}$ + $24^{2}$

       = 676

BD = $\sqrt{676}$

     = 26

BD = 26 cm

so that,

the circumference of BCD = 10 + 24 + 26

                                         =   60 cm

C. To calculate the circumference of the BEC triangle,

AC = 26 cm, AE = 13 cm

CE = 26 - 13

     = 13 cm

CE = 13 cm

The circumference of the BEC triangle = 13 + 13 + 10

                                                                 = 36 cm

D. The circumference of the DEC triangle = 13 + 13 + 24

                                                                 = 50 cm