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SOVA2 [1]
3 years ago
15

Three rocks, each of varying mass and volume, are released from a window at the same time. The window is at height h above the g

round. Which rock, if any, will strike the ground at the fastest speed? Assume that air resistance affects the rocks equally.
all three rocks will achieve the same speed

the largest rock

the most massive rock

the densest rock
Physics
1 answer:
d1i1m1o1n [39]3 years ago
4 0
All three rocks will achieve the same speed
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Organizing and interrupting information from the sense is called
NeTakaya

I think It is Perception


5 0
3 years ago
a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exer
k0ka [10]

Answer: - 7500N

Explanation:

Given the following :

Initial Velocity of car = 108km/hr

Time taken to stop after applying brakes = 4s

Mass of passengers in car = 1000kg

Force exerted by the brakes on the car =?

After 4s, then final Velocity (V) = 0

Initial Velocity (u) of the car = 108km/hr

108km/hr = (108 × 1000)m ÷ (3600)s = 30m/s

Force exerted = mass(m) × acceleration(a)

Acceleration of car = Change in Velocity with time

a = (v - u) / t

a = (0 - 30) / 4

a = - 30/ 4

a = - 7.5m/s^2

Therefore,

Force exerted = mass(m) × acceleration(a)

Force exerted = 1000kg × (-7.5)m/s^2

Force exerted = - 7500N

5 0
3 years ago
Read 2 more answers
Which measurement can be constant (unchanging)?
katrin2010 [14]
I think it is Velocity
6 0
3 years ago
A coin has a radius of 1.06 cm and a thickness of 1.2 mm. Find its<br><br> volume in m^3.
ANTONII [103]

Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³

4 0
3 years ago
Please help me guys never mind the calculations ​
vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  \\  \frac{1}{R}  =  \frac{3 + 2}{6}  =  \frac{5}{6}  \\ R =  \frac{6}{5}  = 1.2 \:  \: ohm

5.2) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{8}  +  \frac{1}{10}  \\  \frac{1}{R}  =  \frac{5 + 4}{40}  =  \frac{9}{40}  \\ R =  \frac{40}{9}  = 4.4 \:  \: ohm

I hope I helped you^_^

7 0
3 years ago
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