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zhannawk [14.2K]
3 years ago
14

1. An object travels 15 m in 3 s. What is the speed of the car?

Physics
1 answer:
weqwewe [10]3 years ago
3 0

1. Depends on how past the car is moving

2. The velocity is 5m a second heading south

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Peter left Town A at 13:30 and travelled towards Town B at an
pochemuha

Answer:

Explanation: From 13:30 to 15:00, it past: 1 h 30 mins = 1.5

Then, the distance covered by Peter: 40x1.5= 60 miles

From 13:45 to 15:00, it pasts; 1 h 15min =1.25

Then, the distance covered by Philip. 30 x 1.25 = 37.5 miles

Lastly, the distance between them: 60-37.5= 22.5 miles

So the answer is 22.5

4 0
3 years ago
A football player kicks a football in a field goal attempt. When the football reaches its maximum height, what is the relationsh
Stels [109]

At position of maximum height we know that the vertical component of its velocity will become zero

so the object will have only horizontal component of velocity

so at that instant the motion of object is along x direction

while if we check the acceleration of object then it is due to gravity

so the acceleration of object is vertically downwards

so it is along y axis

so here these two physical quantities are perpendicular to each other

so correct answer would be

<em>C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other. </em>

3 0
3 years ago
Read 2 more answers
HOW DO U FEEL WHEN U PLAY OR WATCH BADMINTON?
True [87]

Answer:

I feel exited and happy I enjoy it with my friend

6 0
3 years ago
Name the type of component that has a greater resistance as the current through it increases​
Gnesinka [82]

Answer:

filament bulb, filament lamp

Explanation:

4 0
3 years ago
A Boeing 747 ""Jumbo Jet"" has a length of 59.7 m. The runway on which the plane lands intersects another runway. The width of t
Reika [66]

Answer:

1.7 seconds

Explanation:

To clear the intersection, the total distance to be covered = 59.7 + 25 =84.7m

first we need to find the initial speed to just enter the intersection by using the third equation of motion

v^2 - u^2 = 2*a*s

45^2 - u^2 = 2 * -5.7 * 84.7

u^2 = 45^2 +965.58

u^2 = 2990.58

u = 54.7 m/s

Now for time we apply the first equation of motion

v-u =a * t

t = (v-u)/a = (45 - 54.7)/-5.7 = 1.7seconds

8 0
3 years ago
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