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3 years ago

Find the next two terms of the following sequence: 13, 4, -11, -32,...

1 answer:

6 0

Hum, seems to subtract 9 then subtract 15 then subtract 21
the amount subtracted increases by 6 each time
so then we subtract 27 to get -59
then subtract 33 to get -92

the next two terms are -59 and -92

You might be interested in

Which calculation and answer show how to convert 3/12 to a decimal<br> Plz help ASAP

DedPeter [7]

Answer:

Its C

Step-by-step explanation:

It is C becuase when converting a fraction to a decimal, you just divide the numerator by the denominator

Basically solve the fraction

3/12=1/4

1/4 is a bencmark so right away you should know that should equal to 0.25 since its a quarter.

Or you can always look it like this

3 is the numerator

the “/“ between is basically ”divided by”

And the 12 is the denominator

Now read the equation in that order

3/12= 3 DIVIDED BY 12

There you go!

6 0

3 years ago

The left and right page numbers of an open book are two consecutive integers whose sum is 321

PIT_PIT [208]

Answer:

160,160

Step-by-step explanation:

let the first page be X

second one be x+1

x+x+1=321

2x=320

x= 320÷2=160

pages 160 161

6 0

3 years ago

Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer

Vinil7 [7]

Answer:

The factors of $2(x+y)^2-9(x+y)-5$ is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=> $2(x+y)^2-9(x+y)-5$

To Find:

The factors of the polynomial =?

Solution:

Lets assume k = (x+y)

Then $2(x+y)^2-9(x+y)-5$ can be written as $2k^2-9k-5$

Now by using quadratic formula

k = $\frac{-b\pm\sqrt{(b^2-4ac}}{2a}$

where

a= 2

b= -9

c= -5

Substituting the values, we get

k = $\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}$

k = $\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}$

k = $\frac{-(-9) \pm \sqrt{(81+40)}}{4}$

k = $\frac{-(-9) \pm \sqrt{(121)}}{4}$

k = $\frac{-(-9) \pm 11}}{4}$

k= $\frac{ 9 \pm 11}{4}$

k = $\frac{20}{4}$ k = $\frac{-2}{4}$

$k_1 =5$ $k_2 = -\frac{1}{2}$

$2k^2-9k-5= 2(k-5)(k+\frac{1}{2})$

Solving the RHS we get

$\frac{2}{2}(k-5)(2k+1)$

$(k-5)(2k+1)$

Substituting k = x+y

$((x+y)-5)(2(x+y+1)$

$((x+y)-5)(2x+2y+1)$

5 0

3 years ago

Please answer!!!! IMAGE BELOW

I am Lyosha [343]

Answer:

Your answer to the problem is D

8 0

4 years ago

Read 2 more answers

Calculate the angle of depression from the

s344n2d4d5 [400]

Answer:

angle of depression ≈ 53.8°

Step-by-step explanation:

the angle of depression is the measure of the angle from the horizontal downwards from the top of the flag pole.

this angle is alternate to ∠ A and is congruent to ∠ A

using the sine ratio in the right triangle

sin A = $\frac{opposite}{hypotenuse}$ = $\frac{25}{31}$ , then

∠ A = $sin^{-1}$ ( $\frac{25}{31}$ ) ≈ 53.8° ( to 1 d.p )

Angle of depression ≈ 53.8°

6 0

2 years ago