A mole or fraction of a mole represents a specific <span>number of atoms or molecules. The correct option among all the options that are given in the question is the first option or option "a". The other choices in the question are incorrect. I hope that the answer has actually come to your great help.</span>
The decomposition reaction of hydrogen peroxide:
2 H₂O₂(aq) → 2 H₂O(l) + O₂(g)
The order of reaction is : first order reaction.
[H₂O₂]₀ = 12 M at time = 0
[H₂O₂] = 9.5 M at time = 30 minutes
Average reaction rate = - (Δ[reactants] / Δt)
= - (final reactants conc. - initial reactants conc.) / Δt
= - (9.5 M -12 M) / (30 min - 0 min)
= 0.083 mol / L.min
Answer:
373.15 K
Explanation:
Given data:
Temperature in degree Celsius = 100°C
Temperature in kelvin scale = ?
Solution:
To convert the degree Celsius into kelvin scale we add the given degree Celsius into 273.15.
100°C +273.15 = 373.15 K
Answer:
a) Keq = 4.5x10^-6
b) [oxaloacetate] = 9x10^-9 M
c) 23 oxaloacetate molecules
Explanation:
a) In the standard state we have to:
ΔGo = -R*T*ln(Keq) (eq.1)
ΔGo = 30.5 kJ/moles = 30500 J/moles
R = 8.314 J*K^-1*moles^-1
Clearing Keq:
Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6
b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])
4.5x10^-6 = ([oxaloacetate]/(0.20*10)
Clearing [oxaloacetate]:
[oxaloacetate] = 9x10^-9 M
c) the radius of the mitochondria is equal to:
r = 10^-5 dm
The volume of the mitochondria is:
V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L
1 L of mitochondria contains 9x10^-9 M of oxaloacetate
Thus, 4.18x10^-42 L of mitochondria contains:
molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules
Answer:
a)
b)
hours
Explanation:
Given
Surface Area (S) of 250 grams of powder sample 
square meter.
square centimeter
grams/minute
mg per second
gram per cubic meter 
mg/ml
a)
cm /sec
b) Time taken
Time taken to sink
Time in hours
hours
