Answer:

Explanation:
(a) Balanced equation
2HCl + Ca(OH)₂ ⟶ CaCl₂ + 2H₂O
(b) Moles of Ca(OH)₂

(c) Moles of HCl

(d) Molar concentration of HCl

The molar concentration of the HCl was 
Answer:
2.81 × 10⁶ mm³
2.81 × 10⁻³ m³
Explanation:
Step 1: Given data
Length (l): 250 mm
Width (w): 225 mm
Thickness (t): 50 mm
Step 2: Calculate the volume of the textbook
The book is a cuboid so we can find its volume (V) using the following expression.
V = l × w × t = 250 mm × 225 mm × 50 mm = 2.81 × 10⁶ mm³
Step 3: Convert the volume to cubic meters
We will use the relationship 1 m³ = 10⁹ mm³.
2.81 × 10⁶ mm³ × 1 m³ / 10⁹ mm³ = 2.81 × 10⁻³ m³
Answer:
850g/min
Explanation:
The reaction expression is given as:
P₄ + 5O₂ → P₄O₁₀
Given that:
Number of moles of product = 1.5moles
Time = 30s = 0.5min
Unknown:
The rate of the reaction = ?
Solution:
Convert the moles given to mass of the product.
So;
Mass of product = number of moles x molar mass
Molar mass of P₄O₁₀ = 4(31) + 10(16) = 284g/mol
Mass of product = 1.5moles x 284g/mol = 426g
So;
Reaction rate =
=
= 850g/min
Answer:- Third choice is correct, 17.6 moles
Solution:- The given balanced equation is:

We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.
From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.
It is a simple mole to mole conversion problem. We solve it using dimensional set up as:

= 17.6 mol KOH
So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.