Answer: i guess the problem is with P(x) => "x = 
", then P(x) is true if that equality is true, and is false if the equality is false.
so lets see case for case.
a) x = 0, and 
= 0. So p(0) is true.
b) x = 1 and 
= 1, so P(1) is true.
c) x = 2, and 
= 4, and 2 ≠ 4, then P(2) is false.
d) x= -1 and = 1, and 1 ≠ -1, so P(-1) is false.
Answer:
≈33.3%
Step-by-step explanation:
First we find the difference of the heights to see what the growth was
24-18 = 6
Then we find what percent 6 is of 18 to see what percentage growth occured
6/18 ≈33.3%
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
[ (3 · 7) - 6 ] · 5 = [ 21 - 6 ] · 5 = 15 · 5 = 75
Answer: i - 60 
the two fives are supposed to be up y but i dont know how to put them
Step-by-step explanation:
