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Ber [7]
3 years ago
15

A month with 31 days has the same number of Mondays and Wednesdays. How many of the seven days of the week could be the first da

y of this month?a. 2b. 3c. 4d. 5e. 6
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer: b. 3

Therefore, we will have the same number of Mondays and Wednesdays if the first day is either Monday, Thursday or Friday. Making 3 possible days

Step-by-step explanation:

Given that there are 31 days in the month.

And there are equal number of Mondays and Wednesdays within a 7 day bracket.

30 - 4(7) = 3days

After four weeks we are left with three days.

So, if the first day is;

Monday - we will have 5 Mondays and Wednesdays each

Tuesday - we have more Wednesday

Wednesday - we will have more Wednesday

Thursday - we will have 4 Mondays and Wednesdays each

Friday - we will have 4 Mondays and Wednesdays each

Saturday - we will have more Monday

Sunday - we will have more Monday

Therefore, we will have the same number of Mondays and Wednesdays if the first day is either Monday, Thursday or Friday. Making 3 possible days

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Step-by-step explanation:

I uploaded a picture of the graph, but you can go to the site, Desmos. Just plug in your equation, and you will get the equation graphed.

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It could be written as:

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Step-by-step explanation:

5 0
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2ax-b=cx+d solve for x​
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7 0
3 years ago
Read 2 more answers
Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

3 0
3 years ago
Read 2 more answers
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