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3 years ago

All equation of motion with examples

Mathematics

2 answers:

Yanka [14]3 years ago

8 0

Answer:

It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion.

...

The three equations are,

v = u + at.

v² = u² + 2as.

s = ut + ½at²

mash [69]3 years ago

3 0

Answer:

Answer is below. Hope this helps you!

Step-by-step explanation:

(i)v = u + at

(ii) s = ut + 1/2 *at²

(iii)2as = v²-u²

Examples:

A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.

72km/h = 20m/s

(i) use v= u+ at

20 = 0 + a*300

20 = 5a

20 / 300= a

1/15 ms² = a

to find distance

use 2as= v²-u²

2 *1/15 * s = (20) - 0²

2/15s = 400

s = 400 * 15/2

s = 3000m = 3 km

a car accelerates with a uniform acceleration of 1m/s². it starts with a velocity of 18km/h and reaches 36 km/h in 5 seconds find the distance travelled.

18 km /h = 5m/s

36km/h = 10m/s

use - s= ut + 1/2at²

s = 5 * 5 + 1/2 * 1 * (5)²

s = 25 + 25/2

s = 37.5 meters

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9 + |-78| - (-22)<br><br> Answer truthfully please.

GuDViN [60]

Answer:

109

Step-by-step explanation:

9 + |-78| - (-22)

Apply the absolute value which states |-x| = x.

9 + 78 - (-22)

Apply the rule that states x - (-y) = x + y.

9 + 78 + 22

Add 9 and 78.

87 + 22

Add 87 and 22.

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4 0

2 years ago

Use the given inverse to solve the system of equations. left brace Start 3 By 3 Matrix 1st Row 1st Column x minus y plus z 2nd C

natka813 [3]

The interpretation of the given question is as follows:

Use the given inverse to solve the system of equations

$x- y - z = -6 \\ \\ 2y + z = -6 \\ \\ 3x -8 y = - \dfrac{1}{2}$

The inverse of $\left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right] is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]$

x =

y =

z =

Answer:

x = - 1.5

y = - 0.5

z = - 5

Step-by-step explanation:

Using the correlation of inverse of matrix AX = B to solve the question above;

AX = B

⇒ A⁻¹(AX) = A⁻¹ B

X = A⁻¹ B

So ;

X = A⁻¹ B

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =$ $\left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =$ $\left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]$

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]$

$\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]$