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vladimir1956 [14]
3 years ago
9

10-^4 in standard form

Mathematics
1 answer:
Harrizon [31]3 years ago
6 0
Question: 10^-4 in standard form

Work:

To write 10^-4 in standard form you just simplify the equation.

10^-4 equals 1/10000 or 0.0001

Final Answer:

10^-4 equals 1/10000 or 0.0001
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Paul placed black and white square tiles on a rectangular floor using the pattern shown below. If the entire floor measures 9 fe
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you have to show the pattern

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The probability that a car has a certain factory defect is 825. The probability that a car has a certain factory defect and need
ipn [44]

Answer:

90.91% probability that a car needs an oil change given that it has a certain factory defect

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: having a factory defect.

Event B: needing an oil change.

The probability that a car has a certain factory defect is 825.

So P(A) = 0.825

The probability that a car has a certain factory defect and needs an oil change is 750.

So P(A \cap B) = 0.75

What is the probability that a car needs an oil change given that it has a certain factory defect

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.75}{0.825} = 0.9091

90.91% probability that a car needs an oil change given that it has a certain factory defect

5 0
4 years ago
Find the area of the trapezoid using the formula using the A=1/2h(b1+b2)
pentagon [3]

Answer:

<em><u>9</u></em>

Step-by-step explanation:

  1. <em>1</em><em>/</em><em>2</em><em> </em><em>bh </em><em>(</em><em>b1+</em><em>b2)</em>
  2. <em>Count </em><em>all </em><em>the </em><em>squares </em><em>for </em><em>the </em><em>base </em><em>(</em><em>6</em><em> </em><em>squares)</em>
  3. <em>Half </em><em>it </em><em>bc </em><em>1</em><em>/</em><em>2</em><em>b</em><em>h</em><em>,</em><em> </em><em>which </em><em>is </em><em>not </em><em>3</em><em>(</em><em>h)</em>
  4. <em>Now </em><em>count </em><em>the </em><em>amount </em><em>of </em><em>squares </em><em>to </em><em>the </em><em>top </em><em>of </em><em>it </em><em>from </em><em>the </em><em>bottom </em><em>(</em><em>3</em><em> </em><em>as </em><em>well</em><em>)</em>
  5. <em>Now </em><em>the </em><em>problem </em><em>is </em><em>3</em><em>(</em><em>3</em><em>)</em><em> </em><em>which </em><em>is </em><em>9</em><em>.</em>
  6. <em>So,</em><em> </em><em>the </em><em>answer </em><em>is </em><em><u>9</u></em>

<em><u>Hope </u></em><em><u>this </u></em><em><u>helps!</u></em><em><u> </u></em><em><u>Comment</u></em><em><u> </u></em><em><u>on </u></em><em><u>it </u></em><em><u>if </u></em><em><u>you </u></em><em><u>need </u></em><em><u>more </u></em><em><u>explanation</u></em><em><u>!</u></em><em><u>:</u></em><em><u>)</u></em>

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