Answer:
The maximum annual variable cost he can have to reach his projection is $1,940
Step-by-step explanation:
Given;
Number of miles drive per year N = 10,000 miles
Total annual Fixed cost F = $3,460
cost per mile(rate) r = $0.54 or less
Total cost = fixed cost + variable cost
Total cost = cost per mile × number of miles
Total cost = r × N = $0.54 × 10,000 = $5,400
Let V represent the total variable cost per year;
F + V ≤ r × N
Substituting the values;
3,460 + V ≤ 5,400
V ≤ 5,400 - 3,460
V ≤ 1,940
The maximum annual variable cost he can have to reach his projection is $1,940
Variance to be zero: only one condition that ll the values or measurements of variable must be same.
variance = summation of (x - a)²
where is x is each data value in the collection
a is average of all data in the collection.
Summation of squares is zero implies that each square is zero.
each x -a must be 0.
Hi there,
θ = 180º + the angle of the right-angled triangle.
For finding the angle we know that the opposite side measures 6 units and the adjacent side measures 8 units. So, the hypotenuse is 10 units.
If we want to find the angle of the right-angled triangle we have to use the following equation.
sin(the angle of the right-angled triangle) = 
⇒ the angle of the right-angled triangle =
≈ 36,87º
So,
θ = 180º + the angle of the right-angled triangle
θ ≈ 180º + 36,87º
θ ≈ 216,87º
sin(θ) = sin(216,87º)
sin(θ) =
sin(θ) = 
If you want to do it using properties:
θ = 180º + |the angle of the right-angled triangle|
⇒ sin(θ) = sin(180º + |the angle of the right-angled triangle|)
Using properties:
⇒ sin(θ) = sin(180º)*cos( |the angle of the right-angled triangle|) + cos(180º)*sin(|the angle of the right-angled triangle|)
Sin (180) = 0
⇒ sin(θ) = cos(180º)*sin(|the angle of the right-angled triangle|)
sin(the angle of the right-angled triangle) = -
And cos(180º) = -1
⇒ sin(θ) = -1* 
⇒ sin(θ) =
⇒ sin(θ) = 
What diagram? There's no diagram.
Answer:
I dont know if you want your answer in Exact form or Mixed Number form so I put both.
Starting Box:
or 2
Box 1:
or 
Box 2:
or 
Box 3:
or 4
Box 4:
or 
Just keep adding
from the last number
like:
