Write an equation of the line that passes through (-1,2) with a slope of 4
1 answer:
Step-by-step explanation:
Hey there!
Given;
The points is; (-1 , 2) and slope is 4.
<em>Note:</em><em> </em><em>Use </em><em>one-point</em><em> formula</em><em>.</em>
<em></em>
<em>~</em><em> </em><em>Put </em><em>all</em><em> values</em><em>.</em>
~ Simplify it.
Therefore, the required equation is; 4x-y+6=0.
<h3><em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em></h3>You might be interested in
Your parabola should look like this image. The vertex is at (-1, 9), and you can use any of the x-intercepts (-4, 0) & (2, 0) or the y-intercept (0, 8) as a second point.
Write 1 2/3 as an improper fraction...
1 = 3/3. Plus the 2/3 makes 5/3.
To add/subtract fractions, they need the same denominator. (bottom number)
We can change the denominator by multiplying the top and bottom of a fraction by the same number. (it will stay equal, like 1/2 and 2/4)
Let's change 5/3 and 3/4 to a denominator of 12.
5/3 = 20/12 (bottom multiplies by 4, so does the top)
3/4 = 9/12 (bottom multiplies by 3, so does the top)
Now we just subtract the 20 minus 9 twelfths. (the twelfths act as a sort of unit)