Y = x² - 4x + 4
y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
</span>

<span>
Answer: 4.47 units</span>
It would be called prime.
Answer:
1. 30
2. 34
Step-by-step explanation:
2(4(3) + 3)
2(12 + 3)
2(15)
= 30
12(3) - 2
36 - 2
= 34
hope this helps :)
Answer:
The correct answer is C.
Step-by-step explanation:
The given equation is;

This implies that;


Let us write in Cartesian coordinates by substituting;



Square both sides;

This implies that;



This is an equation of a parabola that opens upwards with a y-intercept of
.
The correct choice is C