Since
(density = mass/volume), we can get the mass/weight of the liquid by integrating the density
over the interior of the tank. This is done with the integral

which is more readily computed in cylindrical coordinates as

The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8
X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0
( X+3)(X-6)
X=-3. X=6
Don't use the negative
Check 6(7)= 4(8)+10
42=42
Answer:
C
Step-by-step explanation:
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
The diagonals of the Rhombus= d1 & d2=6cm and 8cm
Let the Side=a
As we know that in a Rhombus











<h2>_____________</h2><h3>Again </h3>
we know that in a Rhombus





Perimeter of the rectangle is 20cm.