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Mariana [72]
2 years ago
15

Adam let out 18 feet of string to fly his kite. He then let out 19 feet more before reeling back in 8 feet. How long was his str

ing after reeling back?
Mathematics
1 answer:
shusha [124]2 years ago
3 0
29 feet long after reeling back
You might be interested in
19
nadya68 [22]

Area of the plot = 193 sq.yd.  , Option B is the correct answer.

<h3>What is Area ?</h3>

Area is the space occupied by a flat surface or an object .

It is measured in square units

It has wide daily life importance like in the question mentioned , a plot will be measured in area of the space.

It is given that

A developer buys an empty lot to build a small house.

area of the lot = ?

The figure is incomplete and the complete figure is attached with the answer.

To determine the area the figure needs to be divided into triangles and rectangles as shown in the figure

Area of the first triangle = (1/2) * base * height

By Calculation

base = 17 unit and height = 10 unit

= (1/2) * 17 * 10

= 17*5

=85 sq.unit

Area of the second triangle = (1/2)* 9* 8

=36 sq. unit

Area of the rectangle = base * height

base = 9 unit and height = 7 unit

Area = 9*7= 63 sq.unit

Area of the last triangle = (1/2) * 2*9

= 9 unit

The area of the plot = 85+36+63+9

Area of the plot = 193 sq.yd.

Therefore , Option B is the correct answer.

To know more about Area

brainly.com/question/27683633

#SPJ1

4 0
1 year ago
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
The distance between earth and moon is 384000000 m. this distance can be expressed as ____m
zalisa [80]

This distance can be expressed as 3.84× 10^{8} m.

What is distance with example?

  • Distance is a scalar quantity.
  • The distance of an object can be defined as the complete path travelled by an object.

Given the distance between the earth and the moon is 384000km

Representing in exponential notation,

=384000×1000m  [∵1km=1000m]

=384× 10^{6} m

=3.84× 10^{8} m

Learn more about distance

brainly.com/question/22698433

#SPJ4

<u>The correct question is -</u>

The distance between the Earth and the moon is approximately 384000 km.  this distance can be expressed as ____m.

5 0
2 years ago
Simplify the expression -3 (b-7)
Nataliya [291]
Simply distribute the -3 across the b and -7.

-3(b - 7) = (-3 * b) + (-3 * -7) = -3b + 21

Hope this was helpful, if it wasn't just drop me a DM explaining what didn't make sense.
5 0
3 years ago
A closed container has 5.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams.
MatroZZZ [7]

Answer:

The correct option is the last one (0,84 grams, because (5.04 × 1.67) × (10^23 x 10^-24) = 8.4168 x 10^-1))

Step-by-step explanation:

The first step is to think that you have to multiply the number of atoms for the weight of each atom.

When you work with scientific notation, you should solve the operation for numbers and for the ten base. In this case you solve 5.04 x 1.67 and then the product of the ten bases. For this product you have to sum the exponents of the ten base 23 + (-24) = -1.

Summarizing.... 5.04 x 10^23 x 1.67 x 10^-24 = (5.04 x 1.67) x (10^23x10^-24)  ⇒ 5.04 x 10^23 x 1.67 x 10^-24 = 8.4168 x 10^-1

⇒ 5.04 x 10^23 x 1.67 x 10^-24 = 0,84168.

4 0
3 years ago
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