Question

Which exponential function has an initial value of 2?

Answer 1

Answer:

The correct option is A) $f(x)=2(3^{x})$ has an initial value of 2 .

Step-by-step explanation:

We need to find the exponential function has an initial value of 2

To check function which has an initial value of 2, we put $x=0$

Check for A) $f(x)=2(3^{x})$

Put x=0

$f(0)=2(3^{0})$

$f(0)=2$

so, this is the function has an initial value of 2

Therefore, the correct option is A) $f(x)=2(3^{x})$ has an initial value of 2 .

Answer 2

A) f(x) = 2(3^x) is the answer