Someone please help!! I would really appreciate it! This is my math test!

Mathematics

2 answers:

jolli1 [7]3 years ago

5 0

X should be 13 not sure about y

Alborosie3 years ago

5 0

X=13
Y=13 square root 2 or 18.4
Since the insides of a triangle add up to 180, and we know that one angle equates to 90, and the other two are 45, then both legs are congruent, and that the hypotenuse is leg radical (square root) 2

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What would be the function for this?

coldgirl [10]

Answer:

f(x) = 2x + 4

Step-by-step explanation:

This is an arithmetic sequence

y = a1 + (x - 1)d where a1 = first term and d = common difference so it is

y = 6 + (x - 1)*2

y = 2x + 4 answer

7 0

3 years ago

There are 6 roses, 8 carnations, and 12 tulips. Write the ratio of carnations to all flowers in all three forms (simplify first,

Norma-Jean [14]

Your answer is 8 to 26

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3 0

3 years ago

Evaluate: 6-(2/3)^2 A. 17/3 B. 52/3 C. 49/9 D. 50/9

Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

....................................................................................................................................

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)

$\dag\textsf{Acronym \: PEMDAS}$

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is $\mathsf{6-(\cfrac{2}{3})^2}$

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain $\mathsf{6-\cfrac{4}{9}}$ .

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: $\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}$ . Now let's multiply the denominator and the numerator of the first fraction times 9: $\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}$ .

See, now the fractions have the same denominator. All we should do now is subtract the numerators: $\mathrm{\cfrac{50}{9}}$ .