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LiRa [457]
3 years ago
5

what do you call a relation where each element in the domain is related to only one value in the by some rules​

Mathematics
1 answer:
mario62 [17]3 years ago
4 0
A function is a relation (rule) that assigns each element in the domain to exactly one element in the range.
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Please help ! Please help!
riadik2000 [5.3K]

Answer:

The answer is 75 degrees.

Step-by-step explanation:

The explanation is that the the supplementary angle to 80 is 100 since a straight line has an angle of 180, now the 100 degree angle is congruent to the angle x + 25 which means that x + 25 is equal to 100 so x is 75

6 0
2 years ago
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Rock jaw spends a total of $80 each week for karate lessons in ballet lessons if the amount spent on karate lessons increases $1
algol [13]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
2 years ago
What is the unit rate of a graph
tiny-mole [99]
When you are looking for a unit rate in a graph you want to know how much the dependent (y) variable will increase by when the independent (x) variable is increased by one
6 0
3 years ago
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This is due at 11:59 and urgent please answer this, tyyy :))
serious [3.7K]

Answer:

(0,-5). y=mx+b or -5=0 × 0+b, or solving for b: b=-5-(0)(0). b=-5.

(2,-5). y=mx+b or -5=0 × 2+b, or solving for b: b=-5-(0)(2). b=-5.

y=-5

8 0
2 years ago
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