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Romashka-Z-Leto [24]
3 years ago
8

Which ordered pair is the solution to the system of equations?

Mathematics
1 answer:
brilliants [131]3 years ago
3 0
X+y=-1
3x-y=21
add them equations

x+y=-1
<u>3x-y=21 +</u>
4x+0y=20

4x=20
divide by 4
x=5

x+y=-1
5+y=-1
minus 5 both sides
y=-6

(x,y)
(5,-6)

D is answer
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Please Help!!!!
Iteru [2.4K]

Step-by-step explanation:

Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC

To prove = ∠3= 49°

Solution:

In figure, m∥n cut by traversal t.

So,  ∠DEF = ∠ABC(alternative exterior angles)

∠1 + ∠2 = ∠4 + ∠5

∠ABC = ∠1 + ∠2 = 50° + 48° = 98°

Also given that s bisect angles ∠ABC.

∠4 = ∠5

∠ABC = ∠4 + ∠5 = 98°

∠4 + ∠4 = 98°

2∠4 = 98°

∠4 = 49°

∠4= ∠3 = 49° (vertically opposite angles)

∠3 = 49° ,hence proved

5 0
3 years ago
Help pleaseee?<br> thank you
Artist 52 [7]
Cos θ = 35/37
θ = cos^{-1} (35/37)
θ = 18.9 degrees or B
6 0
4 years ago
What is 2x^2y^3/-8xy^4
Ne4ueva [31]
\dfrac{2x^2y^3}{-8xy^4}=-\dfrac{2}{8}\cdot\dfrac{x^2}{x}\cdot\dfrac{y^3}{y^4}=-\dfrac{1}{4}\cdot\dfrac{x}{1}\cdot\dfrac{1}{y}=\boxed{-\frac{x}{4y}}
6 0
3 years ago
A playground is in the shape of a square with each side equal to 109 yards. It has skating rinks in the shape of the quadrants o
I am Lyosha [343]

Answer:

radius = 30 yd , cost of cement = $7065

Step-by-step explanation:

First we will find the area of the circular sectors. From that we can find the cost of cement and their radius.

The area of the playground is ...

playground area = (109 yd)^2 = 11,881 yd^2

Then the area of the skating rinks is:

rink area = playground area - remaining field

rink area = 11,881 yd^2 - 9,055 yd^2 = 2,826 yd^2

Then the cost of cement for the rink area is ...

(2826 yd^2)($2.50 yd^2) = $7065

The four quarter-circle skating rinks add to a total area of a full circle. That area is given by ...

A = πr^2

Put the values in the formula:

2826 = 3.14r^2

Divide both sides by 3.14

900 = r^2

By taking square root at both sides we get,

30 = r

The radius of each quadrant is 30 yards....

6 0
3 years ago
The graph below represents the function f.
OLEGan [10]

Answer: А.

The function f intersects the x-axis at two points, and the function g never intersects the x-axis.

Step-by-step explanation:

In the graph we can see f(x), first let's do some analysis of the graph.

First, f(x) is a quadratic equation: f(x) = a*x^2 + b*x + c.

The arms of the graph go up, so the leading coefficient of f(x) is positive.

The vertex of f(x) is near (-0.5, -2)

The roots are at x = -2 and x = 1. (intersects the x-axis at two points)

Now, we know that:

g(x) has a positive leading coefficient, and a vertex at (0, 3)

As the leading coefficient is positive, the arms go up, and the minimum value will be the value at the vertex, so the minimum value of g(x) is 3, when x = 0.

As the minimum value of y is 3, we can see that the graph never goes to the negative y-axis, so it never intersects the x-axis.

so:

f(x) intersects the x-axis at two points

g(x) does not intersect the x-axis.

The correct option is A.

6 0
3 years ago
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