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qwelly [4]
3 years ago
10

Given the functions f(x) = 2x2 - 8x, g(x) = x2 - 6x + 1, and h(x) = -2x2, rank them from least to greatest based on their axis o

f symmetry. (2 points)
g(x), f(x), h(x)

f(x), g(x), h(x)

h(x), f(x), g(x)

h(x), g(x), f(x)
Mathematics
2 answers:
Mandarinka [93]3 years ago
6 0
Axis of symmetry of h(x)   is x = 0

for f(x) its x = 2 
and for g(x) its  x = 3

so its 
 option 3

Nataly [62]3 years ago
4 0

Answer:

h(x), f(x) , g(x)

Step-by-step explanation:

f(x) = 2x^2 - 8x

Axis of symmetry at x=\frac{-b}{2a}, a=2, b=-8

x=\frac{-b}{2a}

x=\frac{-(-8)}{2(2)}=2

g(x) = x^2 - 6x + 1, a= 1, b=-6

x=\frac{-b}{2a}

x=\frac{-(-6)}{2(1)}=3

h(x) = -2x^2, a=-2, b=0

x=\frac{-b}{2a}

x=\frac{-(0)}{2(-2)}=0

Now rank the function based on their axis of symmetry

h(x), f(x) , g(x)

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Through how many radians does the minute hand of a clock rotate from<br> 12:50 PM to 1:20 PM?
Dahasolnce [82]

Answer:

655Step-by-step explanation:

5

7 0
3 years ago
What expression is the simplified form of “-12+5a-a-6a+8a+8+3a”? Please explain your reasoning.
kramer

Combine like terms:

-12 + 5a - a - 6a + 8a + 8 + 3a

-12 + 5a - a - 6a + 8a + 8 + 3a

5a - a = 4a

4a - 6a = -2a

-2a + 8a = 6a

6a + 3a = 9a

-12 + 8 = -4

Answer

9a - 4

4 0
3 years ago
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Is this correct?<br><br> Help
Mkey [24]

Everything except for 4 is correct, number 4 is c.


7 0
3 years ago
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When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one
Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that p = 0.75

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

P(X = 6) + P(X < 6) = 1

We want P(X < 6). So

P(X < 6) = 1 - P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18

P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82

0.82 = 82% probability that at least one party will not order drinks

5 0
3 years ago
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Can you please help me solve this question using cross multiplication? 2.1/27=2 1/3/0.3p
ANEK [815]
I got p= 14/135
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7 0
3 years ago
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