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Rainbow [258]
3 years ago
10

When can you pull a number out from under the radical?

Mathematics
1 answer:
Volgvan3 years ago
7 0

Answer:

You can take out anything that is a perfect square

Step-by-step explanation:

For Example, a perfect square would be considered

64

36

to get a perfect square you multiply a number by itself

for example,

8 x 8 = 64

6 x 6 = 36

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Estimate the solution to the system of equations 7x−y=7 x+2y=6 ​i need help
Yanka [14]

Answer:

(4/3, 7/3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations of using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

7x - y = 7

x + 2y = 6

<u>Step 2: Rewrite Systems</u>

Equation: x + 2y = 6

  1. [Subtraction Property of Equality] Subtract 2y on both sides:                    x = 6 - 2y

<u>Step 3: Redefine Systems</u>

7x - y = 7

x = 6 - 2y

<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                                                                                                7(6 - 2y) - y = 7
  2. Distribute 7:                                                                                                    42 - 14y - y = 7
  3. Combine like terms:                                                                                       42 - 15y = 7
  4. [Subtraction Property of Equality] Subtract 42 on both sides:                    -15y = -35
  5. [Division Property of Equality] Divide -15 on both sides:                             y = 7/3

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x + 2y = 6
  2. Substitute in <em>y</em>:                                                                                                x + 2(7/3) = 6
  3. Multiply:                                                                                                           x + 14/3 = 6
  4. [Subtraction Property of Equality] Subtract 14/3 on both sides:                  x = 4/3
7 0
3 years ago
Number four please help. Whatever helps gets a Brainly award
pashok25 [27]
29.99 + 35.00 + 3.25 + 3.25 = 71.49

125.00 - 71.49 = 53.51

53.51 ÷ 22.50 = 2.4 = 2

She can buy 2 pairs of shoes.

Hope this helps!!
~Kiwi
8 0
4 years ago
Find the slope of the line that passes through (1,6) and (4,4)
Vadim26 [7]

Answer:

y=-2/3x+20/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-6)/(4-1)

m=-2/3

y-y1=m(x-x1)

y-6=-2/3(x-1)

y=-2/3x+2/3+6

y=-2/3x+2/3+18/3

y=-2/3x+20/3

8 0
3 years ago
Look at the picture<br>​
Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
6-3y+(-7y)+5.6 i really need answers
lianna [129]

Answer:

+2 • (25y + 29)/5

Step-by-step explanation:

6 0
2 years ago
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