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andreyandreev [35.5K]
4 years ago
11

Line segment BD divides trapezoid ABCE into a rectangle and a right triangle as shown. What is the perimeter of the trapezoid?

Mathematics
2 answers:
Serhud [2]4 years ago
3 0
Yes, there is a perimeter for the line of the trapezoid. 
Firdavs [7]4 years ago
3 0

Answer:

\left[\begin{array}{ccc}A&49\\B&69&CorrectAnswer\\C&76\\D&96\\E&133\end{array}\right]

\left[\begin{array}{ccc}Find&The&Perimeter\end{array}\right]

AddTheLengthsOfAll4sides



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M. MRO = 127° m. MRP = 87º and m. NRQ = 83<br> Find m NRP
stiks02 [169]

Answer:

don't know answer what is answee

5 0
3 years ago
Algebra 1 Honors
Paul [167]

Answer:

19200

brainliest if correct

Explanation

12% of 120,000 = 14400

14400x7 = 100800

120,000 - 100800 = 19200

8 0
3 years ago
Niah packed 24 dozen candles into 3 boxes. She packed an equal number of candles into each box. How many candles did Niah pack i
pshichka [43]

8 because 24 candles going into 3 boxes is 24 divided by 3 which is 8

8 0
3 years ago
A company is deciding which box to use for their merchandise. The first box measures 8 inches by 6.25 inches by 10.5 inches. The
Marat540 [252]
Ok so material needed=surface area
SA=2(LW+LH+WH)
note: LW means legnth times width
so

first box is
8 inches by 6.25 by 10.5
assign them
8=legnth
6.25=width
height=10.5
SA=2(8 times 6.25+8 times 10.5+6.25 times 10.5)
SA=2(50+84+65.625)
SA=2(199.625)
SA=399.25


second box
9 by 5.5 by 11.75
L=9
W=5.5
H=11.75
SA=2(9 times 5.5+9 times 11.75+5.5 times 11.75)
SA=2(49.5+105.75+64.625)
SA=2(219.875)
SA=439.75


so we now have

first box=399.25 in^2
second box=439.75 in^2

439.75>399.25
second box needs more material


4 0
4 years ago
Solve for x: -5 &lt; 8x + 11 &lt; 19
vladimir1956 [14]

Answer:

-2<x<1

Step-by-step explanation:

-5 < 8x + 11 < 19

Subtract 11 from all sides

-5-11 < 8x + 11-11 < 19-11

-16 < 8x<8

Divide by 8

-16/8 < 8x/8 <8/8

-2<x<1

6 0
3 years ago
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