What is the equation of a circle with a center of (-2, -1) and radius of √2?
2 answers:
Answer:
(x + 2)² + (y + 1)² = 2
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius.
Here (h, k) = (- 2, - 1) and r = , thus
(x - (- 2))² + (y - (- 1))² = ( )², that is
(x + 2)² + (y + 1)² = 2 ← equation of circle
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Answer:
- See below
Step-by-step explanation:
<u>Given system:</u>
- y ≥ 2x + 1
- y ≤ 2x – 2
The solution is the common area shaded by the inequalities.
The lines are parallel because of same slope.
Both lines are solid because of equal sign in both inequalities.
The first inequality has a y-intercept of 1 and shaded area is to the left of the line since the value of y is greater as x increases.
The second inequality has a y-intercept of -2 and shaded area is to the right of the line since the value of y is greater as x increases.
The matching graph is the second picture (or attached below) and there is no solution.
