The rocket would have gone 125 m away in deep space.The speed when it has gone 300 m is 76.7 m/s.
Answer:
The distance the rocket traveled is 125 m. The speed when it has gone 300 m is 76.7 m/s.
Explanation:
According to the equations of motion, if an object is moving with constant acceleration, then the distance travelled by the object with that acceleration and within a specific time can be obtained as
Since the initial velocity is given as u = 0 at t = 0. Then at t = 10 s, the acceleration is given by 2.5 m/.
Thus,
s= 0 + (×2.5×)=125 m.
Thus, the rocket would have gone 125 m away in deep space.
Similarly, if it had gone 300 m then its speed can be determined using the third equation of motion.
Since, here v is unknown and u is known as 0 with a = 2.5 m/.
2× 9.8×300=v²
5880=v²
Thus, the speed v =
So, the speed when it has gone 300 m is 76.7 m/s.
Answer:
energy per unit charge
Explanation:
EMF is energy per unit charge and has unit joule/ coulomb, where joule is unit of energy and coulomb is the unit of charge.
Newton's second law allows finding the answer for the force that attracts the body is 127.4N
Newton's second law indicates that the force that is the interaction between two bodies is directly proportional to the product of the mass and the acceleration.
F = m a
Where the bold letters indicate vectors, F is the force, m the mass, and the acceleration of the body.
When a body is close to the Earth there is an interaction between the body and the planet, we call this interaction weight, it is given by the relationship
W = m g
Where W is the force called weight, m the mass of the body and g the acceleration of the body, which in this case is called the gravity acceleration (g = 9.8 m / s²)
They indicate that the mass of the body is m = 13 kg, let's calculate the weight
W = 13 9.8
W = 127.4 N
In conclusion using Newton's second law we can find the answer for the force that attracts the body is 127.4N
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Newton´s thrid law of motion states that:
Every action has an equal and opposite reaction.
c. equal, opposite.