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Katyanochek1 [597]

3 years ago

15

When the height of the cylinder increased by a factor five from 100 m to 500 m what happened to the sounders gravitational poten

tial energy?

1 answer:

Ivanshal [37]3 years ago

7 0

Answer:

It increased by a factor of 5.

Explanation:

just did the assignment :3

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A 0.200 kg block on a vertical spring with spring constant of 4.65 ✕ 103 N/m is pushed downward, compressing the spring 0.084 m.

vlada-n [284]

Answer:

PEel = PEg

PEel = .5 * k * x^2

= .5 * 4650 * .1^2

= 23.25

PEg= m * g * h

=.2 * 9.81 * h

23.25 = 1.962* h

h = 11.85

4 0

3 years ago

A certain helium-neon laser pointer, emitting light with a wavelength of 632 nm, has a beam with an intensity of 825 W/m2 and a

BabaBlast [244]

Answer:

$N = 1.62 \times 10^{15}$

Explanation:

Energy of each photon is given as

$E = \frac{hc}{\lambda}$

here we will have

$\lambda = 632 nm$

now we will have

$E = \frac{(6.626\times 10^{-34})(3 \times 10^8)}{632 \times 10^{-9}}$

$E = 3.14 \times 10^{-19} J$

now let say there is N number of photons per second

so power due to photons is

$P = N(3.14 \times 10^{-19})$

now intensity is given as power received per unit area

so we have

$I = \frac{P}{A}$

$825 = \frac{N(3.14 \times 10^{-19})}{\pi (1.40 \times 10^{-3})^2}$

$825 = N(5.11 \times 10^{-14})$

$N = 1.62 \times 10^{15}$

5 0

3 years ago

The SI unit of power is???

attashe74 [19]

Answer:

Watts or Wt's

Explanation:Power is the measure of how much energy or work is used per unit time. "Power" = "energy"/"time" The SI unit of power is joules per second (J/s) or Watts (W). In summary, "1 W = 1 J/s = 1 N·m/s = 1 kg·m"^2·"s"^"-3"

6 0

3 years ago

The decomposition of sulfuryl chloride (so2cl2) is a first-order process. the rate constant for the decomposition at 660 k is 4.

Natali5045456 [20]

<span>THIS IS A GAS PHASE REACTION AND WE ARE GIVE PARTIAL PRESSURES . I WRITE IN TERMS OF P RATHER THAN CONCENTRATION : lnPso2cl12=-kt+lnPso2cl1 initial partial pressure Pso2cl12 the rate constant k and the time t lnPso2cl12=(4.5*10-2*s-1)*65*s+ln (375) so lnPso2cl12=3.002 we take the base e antilog: lnPso2cl12=e3.002 Pso2cl12=20 torr we use the integrated first order rate lnPso2cl12=3.002=k*t+ lnPso2cl12=3.002 we use the same rate constant and initial pressure k=4.5*10-2*s-1 Pso2cl12=375 Pso2cl12=1* so2cl12 Pso2cl12=37.5 torr subtract in Pso2cl12 grom both side lnPso2cl12- lnPso2cl12=-kt ln(x)-ln(y)=ln (x/y) ln (Pso2cl12/Pso2cl20)=-kt we get t -1/k*ln(Pso2cl12/Pso2cl20)=t t=51 s</span>

6 0

3 years ago

What capacitor in series with a 100ω resistor and a 18. 0 mh inductor will give a resonance frequency of 1000 hz?

Black_prince [1.1K]

Capacitor in series with a 100Ω resistor and a 18.0 mH inductor will give a resonance frequency of 1000 Hz is 1.38F

Resonance Frequency of a combination of Series LCR circuit is the frequency at which resonance is achieved in a circuit.

Resonance Frequency of a combination of Series LCR circuit is given by:

f = 1 / 2π $\sqrt{LC\\$

where, f is the resonance Resonance Frequency of a combination of Series LCR circuit

L is the Inductance of the inductor

C is the capacitance of the capacitor

Given,

f = 1000Hz

L = 18.0 mH = 0.018H

R = 100Ω

C = ?

On substituting the values in the above-mentioned formula:

1000 = 1 / 2π $\sqrt{0.018C}$

2π $\sqrt{0.018C}$ = 0.001

On solving, C = 1.38 F

Hence, the capacitance of the given capacitor is 1.38F.

Learn more about Resonant frequency here, brainly.com/question/13040523

#SPJ4

5 0

2 years ago