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ANEK [815]
3 years ago
11

A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi

n is?
Physics
2 answers:
nlexa [21]3 years ago
4 0
In order to find the radius of the coin, we need to use:

Ac = V^2 r

In which,  
Ac = acceleration of the coin = 2.2 m/s^2 
V= rotational Speed  =  (18/12) * 2πr
r= Radius

so,
<span>2.2 = 9(π^2)(r^2) / r 
</span><span>= 9(π^2)r
</span>
<span>r = 2.2 / 9(π^2) = 0.02476740044 m . . .or you can rounded it up to 0.025 m</span>

mafiozo [28]3 years ago
4 0

Answer: 24.8 mm

Explanation:

The centripetal acceleration of the edge of the coin is given by:

a=\omega^2 r (1)

where

\omega is the angular frequency

r is the radius of the coin

The frequency of revolution of the coin is equal to the number of spins divided by the time taken:

f=\frac{18}{12 s}=1.5 Hz

And the angular frequency is given by

\omega=2 \pi f=2 \pi (1.5 Hz)=9.42 rad/s

Since we know the centripetal acceleration, a=2.2 m/s^2, we can re-arrange eq.(1) to find the radius of the coin:

r=\frac{a}{\omega^2}=\frac{2.2 m/s^2}{(9.42 rad/s)^2}=0.0248 m=24.8 mm

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