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3 years ago

A number has 6 hundreds, 7 tens, and 34 ones. What is the number?

Mathematics

2 answers:

s2008m [1.1K]3 years ago

8 0

600+ 70 + 34
600 + 104
704

coldgirl [10]3 years ago

7 0

Well 600 so thats there, now we have to add 70 and 34 which makes 104, so since "1" is the hundred we have to add 104 and 600 which gives you 704.
Answer: 704
Hope i helped! :D

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What is implicit differentiation?

defon

Answer:

The process of finding the derivative of dependent variable in an implicit function by differentiating each term separately by expressing the derivative of the dependent variable as a symbol and by solving the resulting expression for the symbol.

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3 years ago

Find the coordinates of the image of point R(4, –1) rotated 270 percent about the origin.

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(4,-1) turns into (1,4) because the equation for that is (x,y)->(y•-1,x)

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2 years ago

you have $895 in your checking account and write checks for $669, plus take $100 in cash out of your account. How much do you ha

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To answer this we just need to set up a equation:-

895 - 669 - 100 = 126.

SO, after these transactions you will have $126 left.

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3 years ago

A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a

natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, . . . , x₂₃ be the actual data observed by the student

The sample means = x₁ + x₂ + . . . , x₂₃ / 23

$= \frac{x_1 +x_2 +...x_2_3}{23}$

= 2.3hr

⇒ $\sum xi =2.3 \times 23 = 52.9hrs$

let x₁ , x₂, . . . , x₂₃ arranged in ascending order

Then x₂₃ was 10 and has been changed to 14

i.e x₂₃ increase to 4

Sample mean $= \frac{x_1 +x_2 +...x_2_3}{23}$

$\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47$

therefore, the new sample mean is 2.47

2) For the old data set

the median is $x_1_2(th)$ values

$[\frac{n +1}{2} ]^t^h value$

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = $[{x_1_2]^t^h value$ remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

$=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)$

The new sample standard sample deviation is calculated as

$= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)$

Now, when we compare (1) and (2) the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)² ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0

3 years ago

I need answers plz help

Andreas93 [3]

You are correct my dad is a math expert!!

7 0

3 years ago

Read 2 more answers