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3 years ago

I need help in my homework here it is Solve the equation for x. x3 = 729

Mathematics

2 answers:

ki77a [65]3 years ago

8 0

Firstly the coefficient, or the number next to the variable, which is x, goes before it. So instead of x3, it's 3x.

So, to solve to find what x is, you need to divide by 3 on both sides of the equal sign.

3x=729

Dividing by 3 on the left cancels out the 3, leaving just the x.

Dividing the other side gets you what x equals.

x= 243

Andrej [43]3 years ago

6 0

x3=729

729/3= 243

x=243

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Answer:

Step-by-step explanation:

Find the area of the rectangle. A = length * width

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Subtract the area of each circle from the area of the rectangle.

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A = (3+6+9+12) * 18

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2 years ago

The points represented by the (x, y) coordinate pairs all lie on line "k". These are the points: (1,3), (2, 1), (3,-1). (4.-3),

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Answer:a

Step-by-step explanation:

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3 years ago

Making x the subject of a formula.

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X is a variable, a variable you have to divide to cancel out

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3 years ago

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3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

3 years ago

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