So,
Since this is independent probability, the probability of the event above occurring is:

First, the probability of landing on heads.

Now, the probability of rolling an even number.
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
Plug it into the equation.

The correct option is C.
The function in vertex form is

(refer to your other post I solved it there).
The general form of quadratic equations in vertex form is

, where (h, k) is the vertex of the parabola.
Here, a = 1, h = -6 and k = -54
Therefore, the vertex is (-6, -54) and it is a maximum because a = 1 is postive.
Answer:
try c
Step-by-step explanation:
What are the three question?